Question

Consider the line y=5x -3 Find the equation of the line that is patellar to this line and passes through the point (-8, -3) Consider the line y=5x -3

Answer 1

Answer:

The equation of the line that is parallel to given line and passes through the point (-8, -3) is: $y = 5x+37$

Step-by-step explanation:

Given equation of line is:

$y=5x-3$

The general form of equation of line in slope-intercept form is written as:

$y = mx+b$

Here m(co-efficient of x) is the slope of the line and b is the y-intercept.

Comparing the given equation with the general form we get

m = 5

Two parallel lines have same slope so the slope of any line parallel to given line will also be 5.

Let m1 be the slope of required line parallel to y=5x-3

Then m1=5

Putting in general form

$y = m_1x+b$

$y=5x+b$

To find the value of b(y-intercept) the given point has to be put in the equation from which the line passes.

The point is (-8,-3)

$-3 = 5(-8)+b\\-3 = -40+b\\b = -3+40\\b = 37$

Putting the value of b and m1, we get

$y = 5x+37$

Hence,

The equation of the line that is parallel to given line and passes through the point (-8, -3) is: $y = 5x+37$