Digital TV uses a digital signal, or series of 0s and 1s, and is much clearer and less prone to interference than analog TV.<span> It improves reception, offers better picture and sound quality, </span>
In analog television, in which the video and audio are carried by analog signals. In digital they are carried with digital encoding.
I think the answer is the third one...
Answer:
<em>This program is written in C++</em>
<em>Comment are used to explain difficult lines</em>
<em>The first program that prints 0 to 20 (in decimal) starts here</em>
#include<iostream>
int main()
{
//Print From 0 to 20
for(int i = 0;i<21;i++)
{
std::cout<<i<<'\n';
}
}
<em>The modified program to print 0 to 20 in hexadecimal starts here</em>
#include<iostream>
using namespace std;
int main()
{
//Declare variables to use in conversion;
int tempvar, i=1,remain;
//Declare a char array of length 50 to hold result
char result[50];
//Print 0
cout<<"0"<<endl;
// Iterate from 1 to 20
for(int digit = 1; digit<21; digit++)
{
//Start Conversion Process
//Initialize tempvar to digit (1 to 20)
tempvar = digit;
while(tempvar!=0)
{
//Divide tempvar by 16 and get remainder
remain = tempvar%16;
if(remain<10)
{
result[i++]=remain + 48;
}
else
{
result[i++] = remain + 55;
}
//Get new value of tempvar by dividing it by 16
tempvar/=16;
}
//Print result
for(int l=i-1;l>0;l--)
{
cout<<result[l];
}
i=1;
cout<<endl;
}
return 0;
}
//The Program Ends Here
See Attachments for program 1 and 2; program 2 is the modified version of 1
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cpp
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cpp
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Because you have to explain how you got it
Integers, Strings, and Objects. Hope this helped, have a great day! :D
