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nadezda [96]
3 years ago
13

The sum of nine consecutive integers; n=middle integer of the nine

Mathematics
1 answer:
VMariaS [17]3 years ago
4 0
(n-4)+(n-3)+(n-2)+(n-1)+n+(n+1)+(n+2)+(n+3)+(n+4)=9n
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