3 years ago

The sum of nine consecutive integers; n=middle integer of the nine

1 answer:

4 0

$(n-4)+(n-3)+(n-2)+(n-1)+n+(n+1)+(n+2)+(n+3)+(n+4)=9n$

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rusak2 [61]

Answer:

you have y so i will guess u mean x your answer for x will be

Step-by-step explanation:

since 33 is ur first number and 11 evenly goes into 33 it will be

Y 34

Y= ----- SUBTRACTED BY -------

33 11

<h2>Y EQUALS Y OVER 33 MINOUS 34OVER 11</h2>

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3 years ago

jenyasd209 [6]

Y = $\frac{ 2x + 216}{x}$

This is because 16 needs to be added to the base amount since the teachers cost is automatically added in.

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marta [7]

The answer would be g=3

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Genrish500 [490]

Answer is 20 % im not sure

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Stels [109]

Answer:

Step-by-step explanation:

di ko po alam kung tama ba

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