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Crazy boy [7]
3 years ago
15

(3,4) (3,5) (3,6) y as a function of x

Mathematics
1 answer:
Nezavi [6.7K]3 years ago
6 0

Answer:

Step-by-step explanation:

y is NOT a function of x because there is not a unique y for each x.

The vertical line through these three points is

x = 3

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I need an answer ASAP
Misha Larkins [42]

Answer:

200

Step-by-step explanation:

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2 years ago
Read 2 more answers
What ordered pair is the solution to -7x+3y=2
goldenfox [79]

Answer:

Step-by-step explanation:

3y=7x+2

y=\frac{7x+2}{3}\\x=1,y=3\\

one pair is (1,3)

go on adding  3 in x=1,you get corresponding value of y.

x=4,y=10,(4,10)

and so on .

7 0
3 years ago
How to factor 5m2-29m+20?
ser-zykov [4K]

Question :

5m^2 - 29m + 20

Steps:

What can u factor to get 20?

you can make 5 and 4 to make 20 so,..

1. Break it into groups

(5m^2 - 4m) + (-25m + 20)

*Factor out m from (5m^2 - 4m) : m(5m - 4)

*Factor out -5 from (-25m + 20) : -5(5m - 4)

2. Then, you can factor out the common term : (5m - 4) because they both have it. And then u would move the m by the -5 so,...

= (5m - 4)(m - 5) <======= <em>Answer</em>


Hope this helped!!!

~Shane


3 0
3 years ago
A public health organization reports that 40%of baby boys 6-8 months old in the United
Sveta_85 [38]

Using the binomial distribution, the probabilities are given as follows:

  • 0.3675 = 36.75% probability that more than 4 weigh more than 20 pounds.
  • 0.1673 = 16.73% probability that fewer than 3 weigh more than 20 pounds.
  • Since P(X > 7) < 0.05, it would be unusual if more than 7 of them weigh more than 20 pounds.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

The values of the parameters for this problem are:

n = 10, p = 0.4.

The probability that more than 4 weigh more than 20 pounds is:

P(X > 4) = 1 - P(X \leq 4)

In which:

P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

Then:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.4)^{0}.(0.6)^{10} = 0.0061

P(X = 1) = C_{10,1}.(0.4)^{1}.(0.6)^{9} = 0.0403

P(X = 2) = C_{10,2}.(0.4)^{2}.(0.6)^{8} = 0.1209

P(X = 3) = C_{10,3}.(0.4)^{3}.(0.6)^{7} = 0.2150

P(X = 4) = C_{10,4}.(0.4)^{4}.(0.6)^{6} = 0.2502

Hence:

P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0061 + 0.0403 + 0.1209 + 0.2150 + 0.2502 = 0.6325

P(X > 4) = 1 - P(X \leq 4) = 1 - 0.6325 = 0.3675

0.3675 = 36.75% probability that more than 4 weigh more than 20 pounds.

The probability that fewer than 3 weigh more than 20 pounds is:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0061 + 0.0403 + 0.1209 = 0.1673

0.1673 = 16.73% probability that fewer than 3 weigh more than 20 pounds.

For more than 7, the probability is:

P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 8) = C_{10,8}.(0.4)^{8}.(0.6)^{2} = 0.0106

P(X = 9) = C_{10,9}.(0.4)^{9}.(0.6)^{1} = 0.0016

P(X = 10) = C_{10,10}.(0.4)^{10}.(0.6)^{0} = 0.0001

Since P(X > 7) < 0.05, it would be unusual if more than 7 of them weigh more than 20 pounds.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

4 0
2 years ago
Translate the phrase, then simplify. Subtract eighty-two from one hundred fifty
emmasim [6.3K]

Answer:

It is 18

Step-by-step explanation:100-82=18

7 0
3 years ago
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