Question

Solve the following inequality for g. Write your answer in simplest form. -5-3(5g-4)≥2g+6-10

Answer 1

Answer:

$g\leq \frac{11}{17}$

Step-by-step explanation:

$-5-3(5g-4)\geq 2g+6-10\\-5+(-15g+12)\geq 2g-4\\-5+(-15g)+12\geq 2g-4\\7-15g\geq 2g-4\\7\geq 17g-4\\3\geq 17g\\\frac{11}{17} \geq g\\g\leq \frac{11}{17}$