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wlad13 [49]
3 years ago
9

Solve -36 4/9 - (-10 2/9) - (18 2/9) A -44 4/9 B -28 C 8 4/9 D 64 3/9

Mathematics
2 answers:
svetlana [45]3 years ago
8 0

Answer:

A. -44 4/9

Step-by-step explanation:

marysya [2.9K]3 years ago
7 0

The answer is A. -44 4/9

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The sum of a polygon's angles are 540.

When you add all the angles together here, you get 456.

Now subtract 456 from 540.

540 - 456 = 84

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3 years ago
Please help me solving this problem.
Illusion [34]

(a) The radius of the circle is the distance the wave travels since it first formed, so if <em>g(t)</em> is the radius of the circle at time <em>t</em>, then it changes at a rate according to

d<em>g</em>/d<em>t</em> = 60 cm/s

Integrate both sides with respect to <em>t</em> to solve for <em>g</em> :

∫ d<em>g</em>/d<em>t</em> d<em>t</em> = ∫ (60 cm/s) d<em>t</em>

<em>g(t)</em> = (60 cm/s) <em>t</em> + <em>C</em>

but <em>C</em> = 0 since the radius at <em>t</em> = 0 must be 0.

<em>g(t)</em> = (60 cm/s) <em>t</em>

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(b) The area of any circle with radius <em>r</em> is <em>πr</em> ². So

<em>f(r)</em> = <em>πr</em> ²

(c) The composition of <em>f</em> with <em>g</em> represents the area of water encircled by the wave at time <em>t</em> :

<em>(f</em> o <em>g)(t)</em> = <em>f(g(t))</em> = <em>π</em> <em>g(t) </em>²

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3 years ago
You are having a discussion about sequences with your classmate. She insists that the sequence 2,3,5,8,12 must be a Arithmatic o
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4 0
3 years ago
Find the length of the leg a of a right triangle with leg length b = 21.5 inches and the hypotenuse c = 31.9 inches. Use a calcu
mylen [45]

The length of the leg a of the right triangle is obtained by applying the Pythagorean theorem which is given as:

\text{opposite}^2+adjacent^2=hypothenus^2

Thus, we have that:

a^2+b^2=c^2

Given that b = 21.5 inches and c = 31.9 inches, we now have:

a^2+(21.5)^2=(31.9^2)a^2+462.25=1017.61a^2=1017.61-462.25a^2=555.36\begin{gathered} a=\sqrt[]{555.36}=23.57 \\ \Rightarrow a=23.6\text{ inches (to one decimal place)} \end{gathered}

Therefore, the length of the leg a of the right triangle is 23.6 inches

4 0
1 year ago
Find the equation of the line tangent to the graph of
garik1379 [7]

Answer:

\displaystyle y=\frac{2\sqrt{3}}{15}x+\frac{\pi-2\sqrt{3}}{6}

Step-by-step explanation:

We want to find the equation of the line tangent to the graph of:

\displaystyle y=\sin^{-1}\big(\frac{x}{5}\big)\text{ at } x=\frac{5}{2}

So, we will find the derivative of our equation first. Applying the chain rule, we acquire that:

\displaystyle y^\prime=\frac{1}{\sqrt{1-(\frac{x}{5})^2}}\cdot\frac{1}{5}

Simplify:

\displaystyle y^\prime=\frac{1}{5\sqrt{1-\frac{x^2}{25}}}

We can factor out the denominator within the square root:

\displaystyle y^\prime =\frac{1}{5\sqrt{\frac{1}{25}\big(25-x^2)}}

Simplify:

\displaystyle y^\prime=\frac{1}{\sqrt{25-x^2}}

So, we can find the slope of the tangent line at <em>x</em> = 5/2. By substitution:

\displaystyle y^\prime=\frac{1}{\sqrt{25-(5/2)^2}}

Evaluate:

\displaystyle y^\prime=\frac{1}{\sqrt{75/4}}=\frac{1}{\frac{5\sqrt{3}}{2}}=\frac{2\sqrt{3}}{15}

We will also need the point at <em>x</em> = 5/2. Using our original equation, we acquire that:

\displaystyle y=\sin^{-1}(\frac{1}{2})=\frac{\pi}{6}

So, a point is (5/2, π/6).

Finally, by using the point-slope form, we can write:

\displaystyle y-\frac{\pi}{6}=\frac{2\sqrt{3}}{15}(x-\frac{5}{2})

Distribute:

\displaystyle y-\frac{\pi}{6}=\frac{2\sqrt{3}}{15}x+\frac{-\sqrt{3}}{3}

Isolate. Hence, our equation is:

\displaystyle y=\frac{2\sqrt{3}}{15}x+\frac{\pi-2\sqrt{3}}{6}

7 0
3 years ago
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