32 because 64 divided by 2 equals 32
Answer:
The standard deviation of the sampling distribution of sample means would be 0.8186.
Step-by-step explanation:
We are given that
Mean of population=23.2 pounds
Standard deviation of population=6.6 pounds
n=65
We have to find the standard deviation of the sampling distribution of sample means.
We know that standard deviation of the sampling distribution of sample means
=
Using the formula
The standard deviation of the sampling distribution of sample means
=

Hence, the standard deviation of the sampling distribution of sample means would be 0.8186.
Answer:
a) 0.1353
b) 0.3679
Step-by-step explanation:
Let's start by defining the random variable T.
T : ''The time (in hours) required to repair a machine''
T ~ exp (λ)
T ~ exp (1)
The probability density function for the exponential distribution is
(In the equation I replaced λ = L)

With L > 0 and x ≥ 0
In this exercise λ = 1 ⇒

For a)





For b)

The event (T ≥ 10 / T > 9) is equivalent to the event T ≥ 1 so they have the same probability of occur



Answer:
The distance is 8 cm
Step-by-step explanation:
The chord and the diameter form one leg and the hypotenuse of a right triangle. The other leg, BD, has length ...
BD² +AB² = AD²
BD² = AD² -AB² = 34² -30² = 256
BD = √256 = 16
The segment from the center of the circle to the midpoint of the chord is the midline of triangle ABD, so is half the length of BD.
distance from AB to the center = 16/2 = 8 . . . cm
Answer:
<u>The approximate total weight of the grapefruits, using the clustering estimation technique is B. 35 ounces.</u>
Step-by-step explanation:
We notice that the weights of the grapefruits given are slightly down or above 7, then we will use <em>7 as our cluster</em> for the estimation, as follows:
Weights
7.47 ⇒ 7
7.23 ⇒ 7
6.46 ⇒ 7
7.48 ⇒ 7
6.81 ⇒ 7
<u>Now we can add up 7 + 7 + 7 + 7 + 7 for the weights of the grapefruits and the approximate total weight is B. 35 ounces.</u>