A car passes a landmark on a highway traveling at a constant rate of 45 kilometers per hour.
Let t be the time taken by second car
So t+1 is the time taken by first car
Distance = speed * time
Distance traveled by first car = 45 * (t+1)
second car passes the same landmark traveling in the same direction at 65 kilometers per hour
Distance traveled by second car = 65 * (t)
When second car overtakes the first car then their distance are same
65 t = 45(t+1)
65t = 45t + 45
Subtract 45 t from both sides
20t = 45
Divide both sides by 20
so 
It took 2.25 hours for the second car to overtake first car
this is the easiest question ever what the fk
Answer:
i think the answer in 14
Step-by-step explanation:
:)
Points equidistant from DE EF are in the bisector of angle DEF
points equidistant from EF DF are in the bisector of angle EFD
the sought after point is the intersection of bisectricess of triangle
Answer:
D. Subtract 9y from both sides of the equation.
Step-by-step explanation:
A. Divide both sides of the equation by 36.
B. Multiply both sides of the equation by 6.
C. Add 9y to both sides of the equation.
D. Subtract 9y from both sides of the equation.
Given:
9y - 6x = 36
To solve for x
Step 1: subtract 9y from both sides
9y - 6x - 9y = 36 - 9y
- 6x = 36 - 9y
Step 2: Divide both sides by -6
- 6x / -6 = (36 - 9y) / - 6
x = (36 - 9y) / - 6
The answer is
x = (36 - 9y) / - 6
