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SSSSS [86.1K]
3 years ago
10

Help me out please, thanks.

Mathematics
1 answer:
Afina-wow [57]3 years ago
8 0

Answer:

The answer is 675.75

Step-by-step explanation:

159 × 4.25= 675.75

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Sam is placing rope lights around the edge of a circular patio with a diameter of 18 feet. The lights come in lengths of 54 inch
andrew-mc [135]
You can find the circumference of the circle with the circumference equals 2pir.
circumference=2pi9
circumference=18pi
circumference=56.55 feet
you can then turn the feet into inches by multiplying by 12
(56.55 feet)x(12inches/foot)=678.58 inches
then divide 678.58 inches by 54 inches to find how many light strands are needed.
(678.58 inches)/(54 inches/strand)=12.57 strands
4 0
3 years ago
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A researcher thinks that a person's mood has an effect on how helpful that person is likely to be. To test this, the researcher
eimsori [14]

Answer:

One possible confound for the experiment is the attitude of the research assistants.

Step-by-step explanation:

A confounder simply means a variable that has impact in influencing both the dependent variable and independent variable, causing a spurious association.

So, we can conclude that the attitudes of the research assistants have positive and negative impacts in determining the reactions of both participants in the experiment.

The rudeness of a research assistant will negatively impact the response of the participant allocated to him/her.

The calmness of the other research assistant will positively impact the response of the participant allocated to him/her.

5 0
3 years ago
What's 49 divided by 261
Tpy6a [65]
.19
Hope this helped!
8 0
3 years ago
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Use integration by parts to derive the following formula from the table of integrals.
emmasim [6.3K]

Answer:

I= (x^n)*(e^ax) /a - n/a ∫ (e^ax) *x^(n-1) dx +C (for a≠0)

Step-by-step explanation:

for

I= ∫x^n . e^ax dx

then using integration by parts we can define u and dv such that

I= ∫(x^n) . (e^ax dx) = ∫u . dv

where

u= x^n → du = n*x^(n-1) dx

dv= e^ax  dx→ v = ∫e^ax dx = (e^ax) /a ( for a≠0 .when a=0 , v=∫1 dx= x)

then we know that

I= ∫u . dv = u*v - ∫v . du + C

( since d(u*v) = u*dv + v*du → u*dv = d(u*v) - v*du → ∫u*dv = ∫(d(u*v) - v*du) =

(u*v) - ∫v*du + C )

therefore

I= ∫u . dv = u*v - ∫v . du + C = (x^n)*(e^ax) /a - ∫ (e^ax) /a * n*x^(n-1) dx +C = = (x^n)*(e^ax) /a - n/a ∫ (e^ax) *x^(n-1) dx +C

I= (x^n)*(e^ax) /a - n/a ∫ (e^ax) *x^(n-1) dx +C (for a≠0)

5 0
3 years ago
HELP QUICK! worth extra points
Vikentia [17]

Answer: <em>3w+4b</em>

Step-by-step explanation:

<em>Take your given equation</em>

<em>w+w+w+b+b+b+b</em>

<em>There are 3 w's and 4 b's</em>

<em>Combine like terms</em>

<em>w+w+w=</em><em>3w</em>

<em>b+b+b+b=</em><em>4b</em>

<em>3w+4b</em>

3 0
3 years ago
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