Can someone help me with this ASAP

Can someone please help this is due at 9

likoan [24]

Answer:

70

Step-by-step explanation:

We have the final part 4x/40 = 7. We can simplify this to x/10 = 7 by dividing the numerator and the denominator by 4. We then multiply both sides by 10 to get x = 70

3 0

3 years ago

Copy the figure below onto a separate sheet of paper. Find the image of the figure under reflections in line m and then line t.

son4ous [18]

The image of the pentagon under reflections in line m and then line t is shown below.

<h3>What is a transformation of geometry?</h3>

A spatial transformation is each mapping of feature shapes to itself, and it maintains some spatial correlation between figures.

Reflection does not change the size and shape of the geometry.

The image of the figure under reflections in line m and then line t.

The reflection of the pentagon DEFG will be given in the figure.

More about the transformation of geometry link is given below.

brainly.com/question/22532832

#SPJ1

8 0

2 years ago

Help Pls! I need this fast!

lesya [120]

Answer: 36

Step-by-step explanation:

$\overline{AB} \cong \overline{BC}$ (Triangle ABC is isosceles)

$m\angle CAB=m\angle CBA=30^{\circ}$ (base angles of an isosceles triangle are congruent)

$\angle MCB=90^{\circ}$ (In triangle CMB, angles in a triangle add to 180 degrees)

$\angle ACM=30^{\circ}$ (triangle sum theorem)

$MB=24$ (30-60-90 triangle CMB)

$AB=12$ (sides opposite congruent angles in a triangle are congruent)

$AB=36$ (segment addition postulate)

3 0

2 years ago

While researching the cost of school lunches per week across the state, you use a sample size of 45 weekly lunch prices. The sta

Drupady [299]

We assume the lunch prices we observe are drawn from a normal distribution with true mean $\mu$ and standard deviation 0.68 in dollars.

We average $n=45$ samples to get $\bar{x}$ .

The standard deviation of the average (an experiment where we collect 45 samples and average them) is the square root of n times smaller than than the standard deviation of the individual samples. We'll write

$\sigma = 0.68 / \sqrt{45} = 0.101$

Our goal is to come up with a confidence interval (a,b) that we can be 90% sure contains $\mu$ .

Our interval takes the form of $( \bar{x} - z \sigma, \bar{x} + z \sigma )$ as $\bar{x}$ is our best guess at the middle of the interval. We have to find the z that gives us 90% of the area of the bell in the "middle".

Since we're given the standard deviation of the true distribution we don't need a t distribution or anything like that. n=45 is big enough (more than 30 or so) that we can substitute the normal distribution for the t distribution anyway.

Usually the questioner is nice enough to ask for a 95% confidence interval, which by the 68-95-99.7 rule is plus or minus two sigma. Here it's a bit less; we have to look it up.

With the right table or computer we find z that corresponds to a probability p=.90 the integral of the unit normal from -z to z. Unfortunately these tables come in various flavors and we have to convert the probability to suit. Sometimes that's a one sided probability from zero to z. That would be an area aka probability of 0.45 from 0 to z (the "body") or a probability of 0.05 from z to infinity (the "tail"). Often the table is the integral of the bell from -infinity to positive z, so we'd have to find p=0.95 in that table. We know that the answer would be z=2 if our original p had been 95% so we expect a number a bit less than 2, a smaller number of standard deviations to include a bit less of the probability.

We find z=1.65 in the typical table has p=.95 from -infinity to z. So our 90% confidence interval is

$( \bar{x} - 1.65 (.101), \bar{x} + 1.65 (.101) )$