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Hunter-Best [27]
3 years ago
5

Please help me ASAP easy problem giving brainlist!!

Mathematics
1 answer:
never [62]3 years ago
8 0

Answer:

x ≥ 1

Step-by-step explanation:

Since it's a closed circle x could also be equal to 1. Also, since the arrow is pointing away from 1 the answer of x is greater than 1, therefore the answer is x ≥ 1.

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ILL GIVE U BRANLIEST
Lady bird [3.3K]

Answer:

1. 0.6p

Step-by-step explanation: Well its quite obvious since its 40%

7 0
2 years ago
5 3/2 x 3 6/7 you have 10 point to do the answer
pogonyaev

Step-by-step explanation:

Conversion a mixed number 5 3/2

to an improper fraction: 5 3/2 = 5 3/2

= 5 · 2 + 3/2

= 10 + 3/2

= 13/2

To find a new numerator:

a) Multiply the whole number 5 by the denominator 2. Whole number 5 equally 5 * 2/2

= 10/2

b) Add the answer from previous step 10 to the numerator 3. New numerator is 10 + 3 = 13

c) Write a previous answer (new numerator 13) over the denominator 2.

Five and three halfs is thirteen halfs

Conversion a mixed number 3 6/7

to an improper fraction: 3 6/7 = 3 6/7

improper fraction: 3 6/7 = 3 6/7

3 · 7 + 6/7 = 21 + 6/7 =27/7

To find a new numerator:

a) Multiply the whole number 3 by the denominator 7. Whole number 3 equally 3 * 7/7

= 21/7

b) Add the answer from previous step 21 to the numerator 6. New numerator is 21 + 6 = 27

c) Write a previous answer (new numerator 27) over the denominator 7.

Three and six sevenths is twenty-seven sevenths

Multiple:

13/2 * 27/7 = 13/2 · 27/7 = 351/14

3 0
2 years ago
In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. Of the students who have a dog as a pet also have cat as a pet.
Travka [436]

Answer:

This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:

"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"

Where X must be a positive number smaller than one, now we can solve it:

we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:

N = 45*(4/5) = 36

And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:

M = 36*X

now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")

M = 36*(1/2) = 18

So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.

5 0
3 years ago
Read 2 more answers
1) It's February and you go to the store to buy some food for your pets. You have a Great
Aleks [24]
<h2>Question:</h2>

1) It's February and you go to the store to buy some food for your pets. You have a Great

Dane and a Savannah cat. The Dane eats 3 times as much as your cat so his food

cost $60 for the big bag and he eats that in one week. The Savannah cats food cost

$15 a bag and it lasts him one week as well. You are there to buy food for the month

and have no more than $300 total to spend. Can you afford a month's worth of food?

a) If you bought the cat 6 weeks worth of food, how many weeks worth can you

buy your Great Dane?

<h2>Answer:  Yes you can afford </h2><h3></h3>
7 0
2 years ago
A librarian has weekends off and has 10 paid vacation days per year, including holidays that fall on weekdays. If his salary is
Free_Kalibri [48]
5*52=260-10=250 32500/250=130
8 0
3 years ago
Read 2 more answers
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