Not an expertise on infinite sums but the most straightforward explanation is that infinity isn't a number.
Let's see if there are anything we missed:
∞
Σ 2^n=1+2+4+8+16+...
n=0
We multiply (2-1) on both sides:
∞
(2-1) Σ 2^n=(2-1)1+2+4+8+16+...
n=0
And we expand;
∞
Σ 2^n=(2+4+8+16+32+...)-(1+2+4+8+16+...)
n=0
But now, imagine that the expression 1+2+4+8+16+... have the last term of 2^n, where n is infinity, then the expression of 2+4+8+16+32+... must have the last term of 2(2^n), then if we cancel out the term, we are still missing one more term to write:
∞
Σ 2^n=-1+2(2^n)
n=0
If n is infinity, then 2^n must also be infinity. So technically, this goes back to infinity.
Although we set a finite term for both expressions, the further we list the terms, they will sooner or later approach infinity.
Yep, this shows how weird the infinity sign is.
We know that
<span>An<span> exterior angle</span></span><span> is one that has its vertex at an outer point of the circumference
</span><span>The measure of the external angle is the semidifference of the arcs that it covers
</span>
so
∠NOP=(70-30)/2-----> 20°
the answer is
<span>∠NOP=20</span>°
Answer:
Step-by-step explanation:
We can combine the -7x and the -2x and the left side to get -9x and the 23 and 13 on the right side to get 36.
This gives us
-9x + 12 = 36
Subtacting 12 from both sides gives us
-9x = 24
dividing by -9 gives us
x = - 8/3
