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Ratling [72]
3 years ago
11

The length of a picture frame is (8u - 12) inches. It’s width is 3/4 of its length. Express the width of the picture frame in te

rms of u.
Pls help I have no idea what to do
Mathematics
1 answer:
dezoksy [38]3 years ago
7 0
3/4(8u-12)..................
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Find the two integers whose sum is -4 and product is -45​
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(+5) and (-9)

Step-by-step explanation:

(+5) + (-9) = -4

(+5) × (-9) = -45

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Which expressions are equivalent to 4^3 〖 x 4〗^(-5)? Choose all answers that are correct. 4^(-2) 1/16 4^(-15) 0.0625 〖16〗^(-1) 1
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Tbh Idek what to tell you

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What is the ratio for 2 red paper clips to 6 blue paper clips? Write it as a fraction.
Dmitriy789 [7]

Answer:

2 over 6 as a fraction simplifies as 1 over three.

Step-by-step explanation:

If you are writing as a fraction, you put 2 over 6 and simplify. Your answer is 1 over 3

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A country is dealing with a serious macroeconomic problem. Businesses
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3 years ago
There are 10 employees in a particular division of a company. Their salaries have a mean of 570,000, a median of $55,000,and a s
harkovskaia [24]

Answer:

a) $160,000

b) $55,000

c) $332264.804

Step-by-step explanation:

We are given that there are 10 employees in a particular division of a company and their salaries have a mean of $70,000, a median of $55,000, and a standard deviation of $20,000.

And also the largest number on the list is $100,000 but By accident, this number is changed to $1,000,000.

a) Value of mean after the change in value is given by;

     Original Mean = $70,000

       \frac{\sum X}{n} = $70,000  ⇒ \sum X = 70,000 * 10 = $700,000

   New \sum X after change = $700,000 - $100,000 + $1,000,000 = $1600000

  Therefore, New mean = \frac{1600000}{10} = $160,000 .

b) Median will not get affected as median is the middle most value in the data set and since $1,000,000 is considered to be an outlier so median remain unchanged at $55,000 .

c) Original Variance = 20000^{2} i.e.  20000^{2} = \frac{\sum x^{2} - n*xbar }{n -1}

    Original \sum x^{2} = (20000^{2} * (10-1)) + (10 * 70,000) = $3,600,700,000

    New \sum x^{2} = $3,600,700,000 - 100,000^{2} + 1,000,000^{2} = 9.936007 * 10^{11}  

    New Variance = \frac{new\sum x^{2} - n*new xbar }{n -1} = \frac{9.936007 *10^{11}  - 10*160000 }{10 -1} = 1.103999 * 10^{11}    Therefore, standard deviation after change = \sqrt{1.103999 * 10^{11} } = $332264.804 .

7 0
3 years ago
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