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3 years ago

Determine if the triangles are congruent. If they are, state how you know.

Mathematics

2 answers:

lapo4ka [179]3 years ago

8 0

Answer:

SAS

Step-by-step explanation:

If you flip the first triangle right side up, we can see that they are congruent in the same exact spots. The two sides are congruent, as well as the angle.

nikitadnepr [17]3 years ago

7 0

Answer:

They are congurrent by SAS criterion. SAS stands for side-angle-side where the angle is in between the 2 lines. In this we can see that 2 lines have been marked as well as the angle in both triangles. SAS is a valid criterion for proving congrurency and therefore these are congurent.

Really hard to explain through typing but hopes this helped

Step-by-step explanation:

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A single conservative force vector F = (4.0x - 12)i hat N where x is in meters, acts on a particle moving along an x axis. The p

serious [3.7K]

Answer:

(4.0x - 12)i . (5/3)i

Step-by-step explanation:

Potential energy = Workdone

Workdone = Force x distance

Force = F = (4.0x - 12)i N

Workdone = 20J

At x= 0

F = -12i

/F/= 12

Workdone = Force x distance

20 = 12 x distance

Distance = 20/12

= 5/3

In the vector form distance is written as (5/3)i

Since Workdone/ Energy is scalar, U can be expressed as a dot product of the vectors of Force and distance :

(4.0 x - 12)i . (5/3)i

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3 years ago

What percent of 125 is 55

DerKrebs [107]

100%/x%=125/55
(100/x)*x=(125/55)*x - we multiply both sides of the equation by x
100=2.27272727273*x - we divide both sides of the equation by (2.27272727273) to get x
100/2.27272727273=x
44=x
x=44 So your answer is 44 ^-^

6 0

4 years ago

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ASHA 777 [7]

Answer:

Step-by-step explanation:

If you look on the axis you can solve the problem

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3 years ago

Find (a) the arc length and (b) the area of a sector.

Brut [27]

Answer:

a) 23.56 ft (2 dp)

b) 58.90 ft² (2 dp)

Step-by-step explanation:

<u>Formula</u>

$\textsf{Arc length}=r \theta$

$\textsf{Area of a sector}=\dfrac{1}{2}r^2 \theta$

$\quad \textsf{(where r is the radius and}\:\theta\:{\textsf{is the angle in radians)}$

<u>Calculation</u>

Given:

$\theta=\dfrac{3 \pi}{2}$
r = 5 ft

$\begin{aligned}\implies \textsf{Arc length} & =r \theta\\& = 5\left(\dfrac{3 \pi}{2}\right)\\& = \dfrac{15}{2} \pi \\& = 23.56\: \sf ft\:(2\:dp)\end{aligned}$

$\begin{aligned} \implies \textsf{Area of a sector}& =\dfrac{1}{2}r^2 \theta\\\\ & = \dfrac{1}{2}(5^2) \left(\dfrac{3 \pi}{2}\right)\\\\& = \dfrac{25}{2}\left(\dfrac{3 \pi}{2}\right)\\\\ & = \dfrac{75}{4} \pi \\\\& = 58.90 \: \sf ft^2\:(2\:dp)\end{aligned}$

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kvv77 [185]

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3 years ago

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