No solutions, since the lines are parallel and never meet. Hope I helped :)
3x - 2y = 5
2y = 3x - 5
y = (3/2) x - 5/2
so the gradient (m) of the required line = -1 / (3/2) = -2/3
using the general form
y - y1 = m(x - x1) , m = -2/3 , x1 = -2 and y1 = 1
y - 1 = -(2/3) ( x - (-2))
y = -(2/3)x - 4/3 + 1
y = -(2/3)x - 1/3
multiply through by 3
3y = - 2x - 1
in standard form its
2x + 3y = -1
Answer:
2/8 = 1/4 = 0.25
Step-by-step explanation:
The rule for this one is called the difference of squares
A^2 - b ^2 = (a+b)(a-b)
Using this rule
N^2 - 62 = (n+ sqrt(62)) (n - sqrt(62))
The solution for this one is to make the statement = 0
0 = (n+ sqrt(62)) (n - sqrt(62))
N can either be +- sqrt(62)
