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Svet_ta [14]
3 years ago
13

5/x+3 take away 1/x-2 equals to 1. solve two possible answers for x

Mathematics
1 answer:
satela [25.4K]3 years ago
8 0

Answer:

<h3><u>Solution</u><u>:</u><u>-</u></h3>
  • First write the given equation

\qquad{:}\longrightarrow\sf \dfrac {5}{x+3}-\dfrac{1}{x-2}=1

\qquad{:}\longrightarrow\sf \dfrac {5 (x-2)-1 (x+3)}{(x+3)(x-2)}=1

\qquad{:}\longrightarrow\sf \dfrac {5x-10-x }{x^2-6x-6} =1

  • use cross multiplication method

\qquad{:}\longrightarrow\sf 5x-x-10=x^2-6x-6

\qquad{:}\longrightarrow\sf x^2-6x-6=4x-10

\qquad{:}\longrightarrow\sf x^2-6x-4x-6+10=0

\qquad{:}\longrightarrow\sf x^2-10x+4=0

  • use quadratic formula

\qquad{:}\longrightarrow\sf x=\dfrac {-b\underline{+}\sqrt {b^2-4ac}}{2a}

\qquad{:}\longrightarrow\sf x=\dfrac {10\underline{+}\sqrt {(-10)^2-4×1×4}}{2×1}

\qquad{:}\longrightarrow\sf x=\dfrac {10\underline{+}\sqrt{100-16}}{2}

\qquad{:}\longrightarrow\sf x=\dfrac {10\underline{+}\sqrt {84}}{2}

\qquad{:}\longrightarrow\sf x=\dfrac {10+\sqrt {84}}{2}\quad or\quad x=\dfrac {10-\sqrt{84}}{2}

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