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astraxan [27]
2 years ago
12

Question 2 (1 point)

Mathematics
1 answer:
Kisachek [45]2 years ago
8 0

Answer:

2. c/8

3. b/15

4. b/25

Those are the only i know-

Step-by-step explanation:

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Halp me plssssssssssssssssssssssssssss
miss Akunina [59]

I think its 180/24 here is my work

\frac{3}{8}\\=\\ \\\frac{9}{24} \\\\\frac{5}{6}\\=\\ \\\frac{20}{24} \\ so you find the lcm of \frac{20}{24} and  \frac{9}{24} = 180/24

5 0
3 years ago
Read 2 more answers
What is the experamental probability that the coin lands on heads?
sammy [17]

Answer:

The experamental probability that the coin lands on head is 50 %

Step-by-step explanation:

Given:

Experiment:

A coin is Toss

Let the Sample Space be 'S' that is total number of outcomes for a coin has been tossed = { Head, Tail }

∴ n ( S ) =  2

Let A be the event of getting a Head on tossing a coin i.e  { Head }

∴ n( A ) = 1

Now,

\textrm{Probability} =\frac{\textrm{outcomes for the experiment}}{\textrm{total number of outcomes}}

Substituting the values we get

P(A) = \frac{n(A)}{n(S)} \\\\P(A) = \frac{1}{2} \\\\P(A) = 0.5\\\\P(A) = 50\%

The experamental probability that the coin lands on head is 50 %

5 0
3 years ago
JUST THE FIRST PART NOT THE DRAWING <br> IM BEGGING AT THIS POINT
Butoxors [25]

Answer:

75 (.2)= 15

75-15=60

The small bag cost $60.

Step-by-step explanation:

6 0
3 years ago
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A football team has a probability of .75 of winning when playing any of the other four teams in its conference. If the games are
Alexeev081 [22]

Answer:

0.3164 = 31.64% probability the team wins all its conference games

Step-by-step explanation:

For each conference game, there are only two possible outcomes. Either the team wins it, or they lose. The probability of winning a game is independent of any other game. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A football team has a probability of .75 of winning when playing any of the other four teams in its conference.

The probability means that p = 0.75, and four games means that n = 4

If the games are independent, what is the probability the team wins all its conference games?

This is P(X = 4). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 4) = C_{4,4}.(0.75)^{4}.(0.25)^{0} = 0.3164

0.3164 = 31.64% probability the team wins all its conference games

4 0
3 years ago
A projectile is launched from ground level with an initial velocity of v0 feet per second. Neglecting air resistance, its height
olya-2409 [2.1K]

Step-by-step explanation:

I've posted solutions in the picture. Rather the ways to solve them. Check and find answers on your own.

Also, I've not solved the problem by differential calculus. You can, obviously, if you're interested. Use it for ease and for tougher equations.

3 0
3 years ago
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