Find x I'm struggling plz help
1 answer:
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Answer:
Therefore the given vectors are orthogonal for b = 0,±3.
Step-by-step explanation:
If and
are two vectors orthogonal, then the dot product of
and
will be zero.
i.e
If and
Given two vectors are (-18,b,9) and (b,b²,b)
Let
and
Therefore,
=(-18).b+b.b²+9.b
= -18b+b³+9b
= b³-9b
Since and
are orthogonal. Then
= 0.
Therefore,
b³-9b= 0
⇒b(b²-9)=0
⇒b =0 or b²=9
⇒b=0 or b =±3
Therefore the given vectors are orthogonal for b = 0,±3.
Answer:
2 real roots
Step-by-step explanation:
To find the number of real roots for a quadratic, we apply the discriminate. The discriminate is the inside portion of the square root from the quadratic formula.
• yields 2 real roots
• yields 1 real root
• [tx]b^2-4ac<0[/tex] yields no real roots
where a=3, b=0, and c=-10
has 2 real roots