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IrinaVladis [17]
2 years ago
11

Find x I'm struggling plz help

Mathematics
1 answer:
alisha [4.7K]2 years ago
8 0

Step-by-step explanation:

the right side of the diagram

9^2 + x^2 = 24^2

81 + x^2 = 576

x^2 = 576 + 81

x^2 = 657

x=√657

the left side of the diagram

9^2 + x^2 = 24^2

81 + x^2 = 576

x^2 = 576 + 81

x^2 = 657

x=√657

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Amelia borrows $13450 for a round-the-world trip. Her repayments are $128 per week for 3 years. How much interest is she charged
ololo11 [35]
First we need to calculate the total payments by multiplying the payment per week times number of weeks in a year times 3 years
Total payments=128×52weeks×3years
=19,968

Subtract the amount borrowed from the total payments to get the interest charged
Interest charged
=19,968−13,450=6,518

Hope it helps!
3 0
2 years ago
Find a number if 7/10 of it is 0.8.
Naddik [55]

Answer:

8/7

Step-by-step explanation:

0.8/0.7=8/7

7 0
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3. Anya budgets $194 for commuting to
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Step-by-step explanation:

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2 years ago
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For what values of b are the vectors [−18, b, 9] and [b, b2, b] orthogonal? (Enter your answers as a comma-separated list. If an
bearhunter [10]

Answer:

Therefore the given vectors are orthogonal for b = 0,±3.

Step-by-step explanation:

If  \vec a and  \vec b are two vectors orthogonal, then the dot product of \vec a and \vec b will be zero.

i.e \vec a. \vec b =0

If  \vec a = x_1\hat i+y_1\hat j +z_1\hat k  and \vec b = x_2\hat i+y_2\hat j +z_2\hat k

\vec a. \vec b=( x_1\hat i+y_1\hat j +z_1\hat k).( x_2\hat i+y_2\hat j +z_2\hat k)

     =x_1 x_2+y_1y_2+z_1z_2

Given two vectors are (-18,b,9) and (b,b²,b)

Let

\vec P= -18 \hat i+b\hat j +9 \hat k

and

\vec Q = b \hat i+b^2 \hat j +b\hat k

Therefore,

\vec P.\vec Q

=( -18 \hat i+b\hat j +9 \hat k).( b \hat i+b^2 \hat j +b\hat k)

=(-18).b+b.b²+9.b

= -18b+b³+9b

= b³-9b

Since \vec P and \vec Q are orthogonal. Then \vec P.\vec Q = 0.

Therefore,

b³-9b= 0

⇒b(b²-9)=0

⇒b =0 or b²=9

⇒b=0 or b =±3

Therefore the given vectors are orthogonal for b = 0,±3.

8 0
3 years ago
Use the discriminant to describe the roots of each equation. Then select the best description.
Scorpion4ik [409]

Answer:

2 real roots

Step-by-step explanation:

To find the number of real roots for a quadratic, we apply the discriminate. The discriminate is the inside portion of the square root from the quadratic formula.

• b^2-4ac>0 yields 2 real roots

• b^2-4ac=0 yields 1 real root

• [tx]b^2-4ac<0[/tex] yields no real roots

3x^2-10=0 where a=3, b=0, and c=-10

b^2-4ac=(0)^2-4(3)(-10)=0+120=120>0) has 2 real roots


6 0
3 years ago
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