All categories

2 years ago

If h(x)=(fog)(x) and h(x) = sqrt x+5, find g(x) if f(x) = sqrtx+2

Mathematics

1 answer:

Katen [24]2 years ago

3 0

Answer: The value of g(x) is x+3.

Step-by-step explanation:

Since we have given that

$h(x)=f\circ g(x)$

Here,

$h(x)=\sqrt{x+5}\\\\and\\\\f(x)=\sqrt{x+2}$

We need to find the value of g(x):

$f(x)=\sqrt{x+2}\\\\f(g(x))=\sqrt{g(x)+2}\\\\h(x)=\sqrt{g(x)+2}\\\\\sqrt{x+5}=\sqrt{g(x)+2}\\\\x+5=g(x)+2\\\\g(x)=x+5-2=x+3$

Hence, the value of g(x) is x+3.

You might be interested in

A chemist is using 378 milliliters of a solution of acid and water. If 18.2% of the solution is acid, how many milliliters of ac

Wewaii [24]

Answer:

If 18.2% of the 378 milliliters of solution is acid, 0.182(378) ml of the solution is acid. Multiplying this out, our final answer is 68.8 ml of the solution is acid.

Let me know if this helps!

7 0

2 years ago

Read 2 more answers

I Have A Comic Book That Has An Advertisement About Advanced Dungeons and Dragons, And I'm Considering Getting The Board Game An

stepan [7]

Answer:

You just play board game I will teach You What You dont know

5 0

2 years ago

Read 2 more answers

write the expressions for when you translate the graph of y = |x+2| a) one unit up b) one unit down c) one unit to the left d) o

irina1246 [14]

Hello!

This question is about which values you are changing when you are transforming an equation.

Let's go through the parent function for an absolute value equation and its various transformations.

$y=a|b(x-c)|+d$

Since we are only looking at horizontal and vertical transformations, we only need to worry about the c and d values.

The c value of a function determines a function's horizontal position, and the d value of a function determines a function's vertical position.

One thing to note here is that the c value is being subtracted from the x value, meaning that if the function is being transformed to the right, you would actually be subtracting that value, while the d value behaves like a normal value, if it is being added, the function is transformed up, and vice versa.

Now that we know this, let's write each expression.

a) $y=|x+2|+1$

b) $y=|x+2|-1$

c) $y=|x+3|$

d) $y=|x+1|$

Hope this helps!

6 0

2 years ago

Y=x-5; domain = {4,6,8}

Lostsunrise [7]

Answer:

Range = {-1, 1, 3}

Step-by-step explanation:

<u><em>The question asks for the range.</em></u>

The function given is

$y=x-5$

The domain is the set of 3 numbers:

Domain = {4,6,8}

We need to find the range.

First, the range is the set of all y-values for which the function is defined.

When we will be given the domain with a set of numbers, the range would be the numbers that we get when we evaluate the the function at those numbers.

So, we evaluate the function (y-values) at x = 4,6, and 8.

At x = 4:

$y=x-5\\y=4-5\\y=-1$