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uysha [10]
3 years ago
8

3 Which of the following represents a function? A {(-2, 1), (-2, 0), (-2, 1), (-2, 2)} B {(-1,0), (0, 1), (1, 2), (2, 3)} C {(1,

3), (3, 1), (2, 3), (3, 2)} D {(5, 5), (5, 4), (5, 3), (5, 2)}​
Mathematics
2 answers:
Margaret [11]3 years ago
7 0

Answer:

Both B and D

Step-by-step explanation:

Because in function there is no repeatation of numbers .

Hope you got it

Mark me as Brainliest

solong [7]3 years ago
4 0

Answer:

A

Step-by-step explanation:

because they want you to look for the number who repeat in the right like A (

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gregori [183]

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use your distributive properties and combine the two equations and just use pemdas.

Step-by-step explanation:

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2 years ago
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Evaluate the following functions at x = 10 q(x)=x^2-2x+2​
Oduvanchick [21]

Answer:

82

Step-by-step explanation:

given:x=10

Evaluating,

(10)²-2(10)+2

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5 0
3 years ago
20 POINTS PLZ HELP!!!!!!!!!!!!!!!!!!!!
mars1129 [50]

Answer:

a = 15

Step-by-step explanation:

First, you have to combine like terms: 5a and 3a, -5, -15, 6, and 4.

You can do it in any order and you will always get a = 15 for your answer.

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4 years ago
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3. At noon Lan is in his blue mini-van 300 km north of Makenna in her Bugatti. Lan heads south
LiRa [457]

Answer:

The rate at which the distance between them is changing at 2:00 p.m. is approximately 1.92 km/h

Step-by-step explanation:

At noon the location of Lan = 300 km north of Makenna

Lan's direction = South

Lan's speed = 60 km/h

Makenna's direction and speed = West at 75 km/h

The distance  Lan has traveled at 2:00 PM = 2 h × 60 km/h = 120 km

The distance north between Lan and Makenna at 2:00 p.m = 300 km - 120 km = 180 km

The distance West Makenna has traveled at 2:00 p.m. = 2 h × 75 km/h = 150 km

Let 's' represent the distance between them, let 'y' represent the Lan's position north of Makenna at 2:00 p.m., and let 'x' represent Makenna's position west from Lan at 2:00 p.m.

By Pythagoras' theorem, we have;

s² = x² + y²

The distance between them at 2:00 p.m. s = √(180² + 150²) = 30·√61

ds²/dt = dx²/dt + dy²/dt

2·s·ds/dt = 2·x·dx/dt + 2·y·dy/dt

2×30·√61 × ds/dt = 2×150×75 + 2×180×(-60) = 900

ds/dt = 900/(2×30·√61) ≈ 1.92

The rate at which the distance between them is changing at 2:00 p.m. ds/dt ≈ 1.92 km/h

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3 years ago
20 POINTS HELP FAST
victus00 [196]

Answer:

brainly.com/question/16576809

Step-by-step explanation:

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