Graph the linear equation.<br><br> 4x+6y=−12

olga_2 [115]

22. B) $65,000,000 per year.

23. B) Education.

Step-by-step explanation:

Step 1; To find the average rate of change in annual budget between the two given years. We divide the difference in values for the two years by the period in between the two years. In 2008, the budget was $358,708,000 while in 2010 it was $488,106,000. The period in between was 2 years i.e 2009 and 2010.

The average rate of change = $\frac{488,106,000-358,708,000}{2}$ = $\frac{129,398,000}{2}$ = $64,699,000 per year.

So the average rate of change was $64,699,000 which approximately equals option B. $65,000,000.

Step 2; To find the human resources program's 2007 to 2010 ratio we divide the value in 2007 to the value in 2010. To find the other similar ratio, we divide the value in 2007 to the value in 2010 for all the other programs and determine which is closest to the human resources program.

Human resources program ratio = $\frac{4,051,050}{5,921,379}$ = 0.6841,

Agricultural / natural resources ratio = $\frac{373,904}{488,106}$ = 0.766,

Education's ratio = $\frac{2,164,607}{3,008,036}$ = 0.7196,

General government's ratio = $\frac{14,347,325}{14,716,155}$ = 0.9749,

Highways and transportation's ratio = $\frac{1,468,482}{1,773,893}$ = 0.827,

Public safety's ratio = $\frac{263,463}{464,233}$ = 0.5675.

The Human resources' program ratio is 0.6841 and the closest is Education's ratio which is 0.7196. So education is the answer.

4 0

3 years ago

Assume that the following data were generated using a valid and appropriate methodology. XYZ Data Analytics, Inc. Received prope

Hitman42 [59]

Using the z-distribution, as we are working with a proportion, the 95% confidence interval for the proportion of consumers who would buy the product at it's proposed price is (0.3016, 0.3830).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

In this problem, we have a 95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so the critical value is z = 1.96.

179 out of 523 members indicated they would buy the new product at the proposed price, hence:

$\pi = \frac{179}{523} = 0.3423$

Then the bounds of the interval are found as follows:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.3423 - 1.96\sqrt{\frac{0.3423(0.6577)}{523}} = 0.3016$

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.3423 + 1.96\sqrt{\frac{0.3423(0.6577)}{523}} = 0.3830$

More can be learned about the z-distribution at brainly.com/question/25890103

4 0

2 years ago

What is the equation of the line that is parallel to the

Ipatiy [6.2K]

Answer:

y = -1/3x -2

Step-by-step explanation:

6 0

2 years ago

The following data shows the low temperature in Vancouver, in degrees Celsius, for two weeks in January one year. 8.90, 8.35, 8.

frutty [35]

There is no option of the box plots, so I have created a version that would represent this data.

To make the box plot you will need the lower extreme, lower quartile, median, upper quartile, and upper extreme.

Please see the attached picture.

5 0

3 years ago

betty tammy and laura went picking apples. betty picked 13 apples, tammy picked 9 apples and laura picked 19 they combined their

jekas [21]

Answer:

41 apples

Step-by-step explanation:

13 apples + 9 apples + 19 apples

41 apples

8 0

3 years ago

Graph the linear equation. 4x+6y=−12