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3241004551 [841]
3 years ago
7

Find the EXACT value of sec (-120 degrees)

Mathematics
2 answers:
Mademuasel [1]3 years ago
7 0

Well sec(-120) = 1/cos(-120).

We know that cos(-120) = -1/2.

So, 1/(-1/2) = -2.

This means that sec(-120) = -2.

kenny6666 [7]3 years ago
3 0
Sec is 1/cos so sec -120 is 1/cos -120 which is -2
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Suppose the sum of two integers is negative. Must both integers be negative? Explain.
mash [69]

Answer:

Not necessarily. There are many ways to write a basic equation with a negative answer. For example, -3-4 = -7. Here 4 is a positive number but because you subtract 4 to 3 or take away 4 from 3 being a negative number and so you get a negative answer. Another example is 6+(-9). There are a couple of ways you can resolve this. My method is to subtract 9 from 6 which gives you 3 and simply add a negative sign.

Let me know if you'd  like more examples. Hope this helps!! Sorry if it is confusing I can explain you in a more simpler way if you'd like.

Step-by-step explanation:

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3 years ago
The larger of two numbers is 15 more than three times the smaller number. If the sum of the two numbers is 63 find the numbers
tatuchka [14]
Let x = the smaller numberLet 3x + 15 = the larger numberx + 3x + 15 = 634x = 48x = 123(12) + 15 = 51
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3 years ago
I need a little help here please make it right :(
IRINA_888 [86]

Answer:

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Step-by-step explanation:

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Read 2 more answers
(3,4) and (12,19) find the equation of the line that passes through it
harina [27]

Answer:

The equation of the line will be:

y=\frac{5}{3}x-1

Step-by-step explanation:

Given the points

  • (3, 4)
  • (12, 9)

Finding the slope between (3, 4) and (12, 9)

\left(x_1,\:y_1\right)=\left(3,\:4\right),\:\left(x_2,\:y_2\right)=\left(12,\:19\right)

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

m=\frac{19-4}{12-3}

m=\frac{5}{3}

The equation of the line can be obtained using the point-slope form of the equation of the line

y-y_1=m\left(x-x_1\right)

substituting the values m = 5/9 and the point (3, 4)

y-4=\frac{5}{3}\left(x-3\right)

y-4+4=\frac{5}{3}\left(x-3\right)+4

y=\frac{5}{3}x-1

Therefore, the equation of the line will be:

y=\frac{5}{3}x-1

5 0
3 years ago
Find a point-slope form for the line with slope 1/5 and passing through the point (-4,-9).
sattari [20]

Answer:

y + 9 = \frac{1}{5}(x + 4)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Here m = \frac{1}{5} and (a, b) = (- 4, - 9) , thus

y - (- 9) = \frac{1}{5}(x - (- 4) ) , that is

y + 9 = \frac{1}{5}(x + 4)

3 0
3 years ago
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