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Korvikt [17]
3 years ago
6

Will mark brainliest, help me answer this question!

Mathematics
2 answers:
zloy xaker [14]3 years ago
4 0

Answer:

135. isosceles triangles have two equal sides/angles. <CBD is 135, from adding 70 and 65.

DanielleElmas [232]3 years ago
3 0

Answer:

135 degrees

Step-by-step explanation:

  • Angle CBD is the sum of angle ABC and angle ABD, so we find these first
  • An Isosceles triangle has 2 equal sides and 2 equal angles
  • Isosceles triangle theorem tells us that the 2 equal angles are respectively opposite the equal sides
  • Since triangle ABC has sides AB=AC, then angle ACB = angle ABC
  • So knowing that angles of triangle add up to 180, then
  • \angle CAB+\angle ACB+\angle ABC=180\\(50)+\angle ACB+\angle ABC=180\\50-(50)+\angle ACB+\angle ABC=180-(50)\\\angle ACB+\angle ABC=130\\But,\angle ACB=\angle ABC,so\\(\angle ABC)+\angle ABC=130\\2\angle ABC=130\\\angle ABC=65
  • Now we do the next triangle to get ABD
  • Since triangle ABD has sides AB=BD, then angle BDA = angle BAD
  • So knowing that angles of triangle add up to 180, then
  • \angle BDA+\angle BAD+\angle ABD=180\\(55)+\angle BAD+\angle ABD=180\\But,\angle BDA=\angle BAD,so\\(55)+(55)+\angle ABD=180\\110+\angle ABD=180\\110-(110)+\angle ABD=180-(110)\\\angle ABD=70
  • Now we said, angle CBD is the sum of angle ABC and angle ABD, so
  • \angle ABC+\angle ABD=\angle CBD\\(65)+(70)=\angle CBD\\\angle CBD=135
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What is the line that goes through (-5,1) and perpendicular to y= 5/4x + 3
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Line RS intersects triangle BCD at two points and is parallel to segment DC. Triangle B C D is cut by line R S. Line R S goes th
Svetlanka [38]

Answer:

The correct options are;

1) ΔBCD is similar to ΔBSR

2) BR/RD = BS/SC

3) (BR)(SC) = (RD)(BS)

Step-by-step explanation:

1) Given that RS is parallel to DC, we have;

∠BDC = ∠BRS (Angles on the same side of transversal)

Similarly;

∠BCD = ∠BSR (Angles on the same side of transversal)

∠CBD = ∠CBD = (Reflexive property)

Therefore;

ΔBCD ~ ΔBSR Angle, Angle Angle (AAA) rule of congruency

2) Whereby  ΔBCD ~ ΔBSR, we therefore have;

BC/BS = BD/BR → (BS + SC)/BS = (BR + RD)/BR = 1 + SC/BS = RD/BR + 1

1 + SC/BS = 1 + RD/BR = SC/BS = 1 + BR/RD - 1

SC/BS = RD/BR

Inverting both sides

BR/RD = BS/SC

3) From BR/RD = BS/SC the above we have by cross multiplication;

BR/RD = BS/SC gives;

BR × SC = RD × BR → (BR)(SC) = (RD)(BR).

7 0
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Answer:

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3 years ago
Which of these properties is enough to prove that a given parallelogram is also a Rectangle?
lozanna [386]

we are supposed to find

Which of these properties is enough to prove that a given parallelogram is also a Rectangle?

As we know from the theorem, if the diagonals of a parallelogram are congruent then the parallelogram is a rectangle.

The other options The diagonals bisect each other is not sufficient because in parallelogram diagonals always gets bisected , parallelogram becomes rectangles only if both the diagonals are of same length.

In a parallelogram The opposite angles and opposite sides are always equal.

Hence the correct option is

The diagonals are congruent.

3 0
3 years ago
Read 2 more answers
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