N^2 + n - 120 = 0
Quadratic formula
a = 1, b = 1, c = -120
n = [-1 plus or minus root(1^2 - 4(1)(-120))] / 2(1)
n = (-1 plus or minus root481)/2
n =(approximately) 10.5 or -11.5
Answer:
Period =½
Equation of midline, y=0
Maximum =2
Minimum=-2
Step-by-step explanation:
The given function is
The period is given by:
The equation of the midline is y=0 since there is no vertical shift
The amplitude of this function is 2 so the range is -2≤y≤2.
Hence the maximum value is 2 and minimum value is -2
Wilson's question is not a statistical question because the students my not a have tall person in their class
We are given that:
side length = 8 3/2 inches = 9.5 inches
the rule for the area is: A = s^2
Substitute with the side length in the rule given to get the area as follows:
Area = s^2 = (9.5)^2 = 90.25 inch^2
The reciprocal would be 9/7 because a reciprocal is when you flip a fraction and put the denominator as the numerator and vice versa.
