Answer: perimeter of triangle ABC to the nearest tenth = 27.4
Step-by-step explanation: Given that
vertices are
A(- 4, 5), B(- 4, - 4) , and C(3,-4)
Length AB = root( [-4-5]^2 + [-4+4]^2)
Length AB = sqr(9^2) = 9
Length AC = root( [-4-5]^2 + [3+4]^2)
Length AC = sqr( 9^2 + 7^2)
Length AC = sqr(130) = 11.4
Length BC = root( [-4+4]^2 + [3+4]^2)
Length BC = sqr( 7^2) = 7
Perimeter = 9 + 11.4 + 7 = 27.4
