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3 years ago

PLEASE HELP

Mathematics

2 answers:

algol133 years ago

7 0

Set up a system of equations.

x+y=110

35x + 50y = 5100

Solve for a variable:

y=110-x

Plug this back into the other equation

35x + 50(110-x)=5100

Solve

35x + 5500 - 50x = 5100

-15x = -400

X = 26.66

Plug that into first equation to solve for y:

X+y=110

26.6+y=110

Y=110-26.6

Y=83.4

26.6 small boxes, 83.4 large

Mandarinka [93]3 years ago

5 0

Let x=large boxes and y=small boxes.

x+y=110

60x+35y=5100

____________

You need to cancel out one of the variables to solve for one. Let's cancel out y.

-35(x+y=110)

-35x-35y=-3850

60x+35y=5100

____________

Add the two equations.

25x=1250

x=50

_____________

Plug in 50 for x into one of the equations to solve for y.

50+y=110

y=60

_____________

50 large boxes

60 small boxes

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Answer:

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Step-by-step explanation:

Given:

18 2/5 - n = -10 1/3.

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Converting the mixed fractions to improper:

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Moving the numbers on one side and variable to the other:

⇒ $\frac{92}{5} +\frac{31}{3}=n$

Now, solving the factions:

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Answer:

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