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lora16 [44]
3 years ago
8

Explain the difference between elements and compounds, a teacher filled

Chemistry
1 answer:
stiv31 [10]3 years ago
6 0

Answer:

Kindly check explanation.

Explanation:

So, without mincing words the solution to this particular Question is given below:

First, an ELEMENT is a that entity that has what is known as the atoms. Although, there might be more elements but the recognized elements are group into the periodic table/chart. Examples of elements are Hydrogen, Helium, Lithium, Beryllium, Boron, carbon, Nitrogen, oxygen, Fluorine, neon, sodium, magnesium, Aluminium and so on.

A COMPOUND consist of different elements that are chemically combined. Examples of compounds are; H2O, CaCO3, H2SO4, HNO3, MgCl2, NaCl, HCl and many more.

Also, elements has the same atoms while componds have different number of atoms since it is a combination of elements.

Finally, ELEMENTS can not be broken down through the use of chemical process while COMPONDS can be broken down through chemical processes.

To the second part of the question. The box that will represent elements will contain balls of the same colors and the balls are not joined together.

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A 25.00 mL sample of the ammonia solution
musickatia [10]

Answer:

1.634 molL-1

Explanation:

The mol ration between NH3 and HCl is 1 : 1

Using Ca Va / Cb Vb = Na / Nb   where a = acid and b = base

Na = 1

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Ca = 0.208 molL-1

Cb = ?

Va = 19.64 mL

Vb = 25.00mL

Solving for Cb

Cb = Ca Va / Vb

Cb = 0.208 * 19.64 / 25.0

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Using the dilution equation;

C1V1 = C2V2

Initial Concentration, C1 = ?

Initial Volume, V1 = 25.00 mL

Final Volume, V2 =  250 mL

Final Concentration, C2 = 0.1634 molL-1

Solving for C1;

C1 = C2 * V2 / V1

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3 0
3 years ago
Please help me with this chem question. Only answer if you know it.
mariarad [96]
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Consider the reaction 2Al + 6HBr → 2AlBr3 + 3H2. If 8 moles of Al react with 8 moles of HBr, what is the limiting reactant?
TiliK225 [7]

Answer:- HBr is limiting reactant.

Solution:- The given balanced equation is:

2Al+6HBr\rightarrow 2AlBr_3+3H_2

From this equation, There is 2:6 mol or 1:3 mol ratio between Al and HBr. Since we have 8 moles of each, HBr is the limiting reactant as we need 3 moles of HBr for each mol of Al.

The calculations could be shown as:

8molAl(\frac{6molHBr}{2molAl})

= 24 mol HBr

From calculations, 24 moles of HBr are required to react completely with 8 moles of Al but only 8 moles of it are available. It clearly indicates, HBr is limiting reactant.

7 0
3 years ago
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