Ask question

Ask question

All categories

3 years ago

14

A large cheese pizza costs $7.50. Each additional topping for the pizza costs $1.35. If the total bill for the pizza Sally order

ed was $12.90, how many toppings did she order? (Enter a whole number, for example, 20, no variables and no words).

1 answer:

konstantin123 [22]3 years ago

5 0

Answer: She ordered 4 toppings.

Step-by-step explanation:

Given: Total cost of pizza = $ 12.90

Cost of pizza =$7.50

Price per topping = $1.35

Let x = Number of toppings,

Total cost of pizza = (Cost of pizza) + (price per topping) × (Number of topping)

$12.90= 7.50+1.35x\\\\\Rightarrow\ 1.35x=12.90-7.50\\\\\Rightarrow\ 1.35x=5.4\\\\\Rightarrow\ x=\dfrac{5.4}{1.35}\\\\\Rightarrow\ x=\dfrac{540}{135}=4$

hence, she ordered 4 toppings.

You might be interested in

HELPPPPPPPP!!!!!!!!!!!!

katovenus [111]

Answer:

A) True

Step-by-step explanation:

The x values, 1 2 3 can go to the y values B L A

However, if there were two lines at 2 1 2 3 going to any of the y values it would not be a function

Here is a picture explaining it.

8 0

3 years ago

Read 2 more answers

The Smith family made a 12-pound turkey for dinner. If each person will eat of a pound, how many

postnew [5]

It will take 12 people to finish the turkey

3 0

3 years ago

Read 2 more answers

Use mathematical induction to prove the statement is true for all positive integers n, or show why it is false:

kondaur [170]

$\text{Proof by induction:}$
$\text{Test that the statement holds or n = 1}$

$LHS = (3 - 2)^{2} = 1$
$RHS = \frac{6 - 4}{2} = \frac{2}{2} = 1 = LHS$
$\text{Thus, the statement holds for the base case.}$

$\text{Assume the statement holds for some arbitrary term, n= k}$
$1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2} = \frac{k(6k^{2} - 3k - 1)}{2}$

$\text{Prove it is true for n = k + 1}$
$RTP: 1^{2} + 4^{2} + 7^{2} + ... + [3(k + 1) - 2]^{2} = \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2} = \frac{(k + 1)[6k^{2} + 9k + 2]}{2}$

$LHS = \underbrace{1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2}}_{\frac{k(6k^{2} - 3k - 1)}{2}} + [3(k + 1) - 2]^{2}$
$= \frac{k(6k^{2} - 3k - 1)}{2} + [3(k + 1) - 2]^{2}$
$= \frac{k(6k^{2} - 3k - 1) + 2[3(k + 1) - 2]^{2}}{2}$
$= \frac{k(6k^{2} - 3k - 1) + 2(3k + 1)^{2}}{2}$
$= \frac{k(6k^{2} - 3k - 1) + 18k^{2} + 12k + 2}{2}$
$= \frac{k(6k^{2} - 3k - 1 + 18k + 12) + 2}{2}$
$= \frac{k(6k^{2} + 15k + 11) + 2}{}$
$= \frac{(k + 1)[6k^{2} + 9k + 2]}{2}$
$= \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2}$
$= RHS$

Since it is true for n = 1, n = k, and n = k + 1, by the principles of mathematical induction, it is true for all positive values of n.

3 0

4 years ago

Kelly has 24 dimes and quarters worth $3.60. How many quarters does she have?

son4ous [18]

Should be around 5 (five) quarters

7 0

4 years ago

Read 2 more answers

33°<br> (3m + 3)<br> ent OR Vertical_<br> Angle Relationship: Complementary OR Supplementary

Reptile [31]

Answer:

complementary

Step-by-step explanation:

because the angles add up to 90°

3 0

3 years ago