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IRINA_888 [86]
3 years ago
7

Solve for k help bestiesss

Mathematics
1 answer:
Kobotan [32]3 years ago
7 0

Answer:

WYM

Step-by-step explanation:

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The topic is about secant tangent angles
Yanka [14]

Answer:

x = 71

Step-by-step explanation:

The chord- chord angle is half the sum of the arcs intercepted by the angle and its vertical angle, that is

x = \frac{1}{2} (92 + 50) = 0.5 × 142 = 71

6 0
3 years ago
Please help I’m doing points
-Dominant- [34]

3 7/8

Hope this helps! :D

6 0
3 years ago
When 5 is added to 2 times a number, the result is 45. find the number.
WINSTONCH [101]
A.

let the number be n.
2n+5=45
2n=40
n=20
3 0
3 years ago
A manufacturer of processing chips knows that 2\%2%2, percent of its chips are defective in some way. Suppose an inspector rando
kipiarov [429]

The data in the question seems a bit erroneous. I am writing the correct question below:

A manufacturer of processing chips knows that 2%, percent of its chips are defective in some way. Suppose an inspector randomly selects 4 chips for an inspection. Assuming the chips are independent, what is the probability that at least one of the selected chips is defective? Lets break this problem up into smaller pieces to understand the strategy behind solving it.

Answer:

The probability that at least one of the selected chips is defective is 0.0776.

Step-by-step explanation:

The question states that the probability of defective chips is 2% i.e. 0.02. Let p denote the probability of selecting a defective chip so, p = 0.02

An inspector selects 4 chips, which means n=4 and we need to compute the probability that at least one of the selected chips is defective. Let X be the number of defective chips selected. We need to compute P(X≥1) which means either 1, 2, 3 or 4 chips can be defective.

We will use the binomial distribution formula to solve this problem. The formula is:

<u>P(X=x) = ⁿCₓ pˣ qⁿ⁻ˣ</u>

where n = total no. of trials

          p = probability of success

          x = no. of successful trials

          q = probability of failure = 1-p

we have n=4, p=0.02 and q=1-0.02=0.98.

We need to compute P(X≥1) which is equal to:

P(X≥1) = P(X=1) + P(X=2) + P(X=3) + P(X=4)

A shorter method to do this is to use the total probability theorem:

P(X≥1) = 1 - P(X<1)

          = 1 - P(X=0)

          = 1 - ⁴C₀ (0.02)⁰(0.98)⁴⁻⁰

          = 1 - (0.98)⁴

          = 1 - 0.9224

P(X≥1) = 0.0776

4 0
3 years ago
Determine if the triangles in the figure are congruent
valkas [14]

Answer:

The triangles are congruent by Angle Side Angle congruency statement and the reason is below.

Step-by-step explanation:

Given:

∠ VUW ≅ ∠ XYW

VW ≅ YW

To Prove:

Δ VUW ≅ Δ XYW

Proof:

In Δ VUW and Δ XYW

∠ VUW ≅ ∠ XYW      ……….{Given}

VW ≅ YW                 ............{Given}

∠ VWU ≅ ∠ XWY    …………..{Vertically Opposite Angles are equal}

Δ VUW ≅ Δ XYW   .….{ By Angle-Side-Angle congruence test}

......Proved

6 0
3 years ago
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