Answer:
Step-by-step explanation:
Original price $595.00
Discount amount 595(0.30) = $178.50
Pre tax price 595.00 - 178.50 = $416.50
tax amount 416.50(0.07) = 29.155 = $29.16
cost to Victoria 416.50 + 29.16 = $445.66
Hi, the answer to this would be x6/9. I'm assuming the x4/3 and x2/3 are fractions and the x's aren't exponents. Now how I got x6/9 is shown here.
1st Step: Started off by regrouping the terms
1/3x3 x^4x^2
2nd Step: we can easily simplify 3x3 to just 9. And now we're left with 1/9x^4x^2
3rd Step: Now we can simplify the 1/9 to just x^4x^2/9
4th Step: Now we can use the product rule which is simple. So We add the exponents and simplify it to just one exponent. So x4+2=6 that simplifies to just x^6.
Final Answer: x^6/9.
Hope this helped you :)
The probability that an adult likes soccer is aged between 18–30 will be 44.4%.
We have an adult who likes soccer.
We have to determine the probability the adult is aged 18–30.
<h3>What is Probability?</h3>
The formula to calculate the probability of occurrence of an event 'A' can be written as -
P(A) =
where -
n(A) = Number of outcomes favorable to event A.
n(S) = Total number of outcomes.
According to question, we have an adult likes soccer.
The answer to this question is based on the hypothesis that the adults between 18 - 30 are highly energetic. To be more precisely - the adults in the range 18 - 24 and 24 - 30 are highly energetic and full of stamina. Above the age 30, the number of adults who like soccer will start to decrease and will hit nearly zero between the age range of 55 - 65 as the adults in this age group found it very difficult to even walk.
Mathematically -
The probability of an event A = an adult likes soccer is aged between 18–30 will be the highest value among the ones mentioned in options.
Hence, the probability that an adult likes soccer is aged between 18–30 will be 44.4%.
To solve more questions on Probability, visit the link below -
brainly.com/question/24028840
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The new figure is formed differently and is not the same as the other ome
Answer should be <span>Both Fred's and Victoria's proofs are correct.</span>