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Gnom [1K]
4 years ago
8

What are the solutions for x^2-4x-6=0

Mathematics
1 answer:
BaLLatris [955]4 years ago
5 0
X (approximately equals) 2+<span>√10
Or 5.162, -1.162</span>
You might be interested in
-5c/8 = 20 what is the value of c
lorasvet [3.4K]

Please try to follow me, as I demonstrate a method of solution. 
This could get complicated.  I'll try to go slowly, and you must
stop me if I do anything that's not clear.

Ready ?

You said that                    -5c/8  =    20

Multiply each side by  8:  -5c     =  160

Divide each side by  5 :   - c      =    32

Multiply each side by -1 :   c      =  -32 

4 0
3 years ago
Help help help ASAP math math
Lorico [155]
29 mg = 0.029 g hope this helps
4 0
3 years ago
Read 2 more answers
Triangle P Q R is shown. The length of P Q is 17, the length of Q R is 15, and the length of P R is 14. Law of cosines: a2 = b2
Maksim231197 [3]

Answer:

P = 57°

Step-by-step explanation:

Given the following :

PQ = 17

QR = 15

PR = 14

Using the cosine formula since the length of the three sides are given:

a2 = b2 + c2 – 2bccos(A)

To find P:

QR^2 = PQ^2 + PR^2 – 2(PQ)(PR)cos(P)

15^2 = 17^2 + 14^2 – 2(17)(14)cos(P)

225 = 289 + 196 - 476 cosP

476*CosP = 485 - 225

476*CosP = 260

CosP = 260/476

CosP = 0.5462184

P = Cos^-1(0.5462184)

P = 56.892029

P = 57°

8 0
3 years ago
What to write it here
Orlov [11]

Answer:

84 degrees

Step-by-step explanation:

Angle A = 83 degrees

Angle B = x degrees

Angle C = 135 degrees

Angle CDE = 122 degrees

We know that the four inner corners of a quadrilateral should add up to 360 degrees. Two supplementary angles will add up to 180 degrees. Adjacent angles on a straight line will always be supplementary. Knowing this, just solve for <ADC and add that amount to <A and <C. Then, subtract that sum from 360 degrees.

<ADC = 180-122 = 58

58+83+135 = 276

360-276 = 84 degrees

7 0
2 years ago
Please help. Thank you in advance.
ivolga24 [154]

Answer:

The second choice is the same so it is the last one

7 0
3 years ago
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