Question

Students ere investigating of a toy car. They performed 2 trials . Trial 1 / time(s) 5 , distance(m) 10, Trial 2 / Time(s) 20 distance(m) 40. What was the average speed of the toy car during the two trials

Answer 1

Answer: The average speed of the toy car during the two trials is 2m/s.

Explanation:

Speed can be defined as a type of scalar quantity in physics through which the rate at which an object travels through a distance is measured in a given amount of time. The formula for determining the speed of a car is:

Speed= distance/ time which has an SI unit of m/s.

From the speed tests carried out on a toy car, the speed of trial 1 is:

Distance= 10 meters

Time= 5 seconds

Therefore trial one speed is 10/5= 2m/s

While the speed of trial 2 is:

Distance= 40meters

Time= 20 seconds

Therefore trial 2 speed is 40/ 20= 2mls

Average speed of the toy car during the two trials is: Sum of both both speeds divided by total number of trials.

Therefore: 2 m/s + 2m/s / 2= 2m/s

From the calculation, the average speed of the toy car during the two trials is 2m/s.