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3 years ago

Find the sin in the triangle

Mathematics

1 answer:

Ierofanga [76]3 years ago

6 0

Answer:

.324 or 18.9 degrees

Step-by-step explanation:

rule is

sine equals opposite over hypotenuse,

cosine equals adjacent over hypotenuse, and

tangent equals opposite over adjacent

soh cah toa

sine = soh = 12/37 = .324

arcsin(.324) or sin^-1(.324) in DEGREES not radians =

18.9 degrees

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Answer:

Sheridan's Work is correct

Step-by-step explanation:

we know that

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$c^{2}=a^{2}+b^{2}$

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$7^{2}+13^{2}=c^{2}$

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Jayden's Work is incorrect, because the missing side is not the hypotenuse of the right triangle

Sheridan's Work

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$7^{2}+b^{2}=13^{2}$

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