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2 years ago

14

2(x - 3) = 2x + 5? Need Help Now

2 answers:

nydimaria [60]2 years ago

8 0

Answer: it has no solutions

Step-by-step explanation:

if im wrong i owe u

PSYCHO15rus [73]2 years ago

8 0

2(x - 3) = 2x + 5 distribute by multiply 2 into the parenthesis.

2x - 6 = 2x + 5

-2x -2x subtract 2x on both sides, 2x's will cancel on both sides.

____________

-6 = 5

Since -6 = 5, there is no solution because -6 cannot equal to 5, which is a false statement. Thus, "C. There is no solution." is the correct answer. Hope this helps :)

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Which equation can be used to solve the following word problem? Seth has 8 more nickels than dimes, and the total value of his c

9966 [12]

Answer:

Seth has 21 nickels

Step-by-step explanation:

Let n represent the number of nickels. Since Seth has 8 more nickels than dimes, then (n-8) is the number dimes.

Nickel is worth 5 cents and dime is worth 10 cents. Thus, n nickels are worth 5n cents and (n-8) dimes are worth 10(n-8) cents. The total value of Seth's coins is $2.35 that is 235 cents, then

$5n+10(n-8)=235.$

Solve this equation:

$5n+10n-80=235,\\ \\15n=235+80,\\ \\15n=315,\\ \\n=21.$

6 0

3 years ago

18. What value of b will make the equation have no solution?<br> 6x + 4 = 4bx – 2

MrRissso [65]

Answer: B is what 6 x +4 = to 4bx - 2 is 6x plus 4 = to 24 then 4bx - 2 is YA so b is Y

5 0

3 years ago

For each graph below, state whether it represents a function.

valina [46]

Graph 1 and 3 are the only functions

6 0

3 years ago

The following table shows the number of hours some students in two universities spend reading each week:

AleksandrR [38]

They do not appear to be symmectric. they seem to line up well

4 0

3 years ago

Write the standard form equation of the ellipse shown in the graph, and identify the foci.

vlada-n [284]

Answer option A

From the given graph is a Vertical ellipse

Center of ellipse = (-2,-3)

Vertices are (-2,3) and (-2,-9)

Co vertices are (-6,-3) and (2,-3)

The distance between center and vertices = 6, so a= 6

The distance between center and covertices = 4 , so b= 4

The general equation of vertical ellipse is

$\frac{(x-h)^2}{b^2} + \frac{(y-k)^2}{a^2}=1$

(h,k) is the center

we know center is (-2,-3)

h= -2, k = -3 , a= 6 and b = 4

The standard equation becomes

$\frac{(x+2)^2}{4^2} + \frac{(y+3)^2}{6^2}=1$

$\frac{(x+2)^2}{16} + \frac{(y+3)^2}{36}=1$

Foci are (h,k+c) and (h,k-c)

$c=\sqrt{a^2-b^2}$

Plug in the a=6 and b=4

$c=\sqrt{6^2-4^2}$

$c=\sqrt{20}$

$c=2\sqrt{5}$ , we know h=-2 and k=-3

Foci are $(-2,-3+2\sqrt{5})$ and $(-2,-3-2\sqrt{5})$

Option A is correct

6 0

3 years ago