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cricket20 [7]
3 years ago
15

Find the perimeter of a train of 100 equilateral triangles if the triangles are joined side to side. Each side is one inch long.

Write an equation to determine the perimeter of the triangle train.
Mathematics
1 answer:
yarga [219]3 years ago
7 0

Answer:

102

Step-by-step explanation:

Each triangle will have a perimeter of 3. When joined, the outside triangles will have 2 sides showing, or 2 inches. The middle 98 will only have one free side, or one inch. This means that 98*1 + 2*2 = 102

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Two children own two-way radios that have a maximum range of 3 miles. One leaves a certain point at 1:00 P.M., walking due north
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Answer:

The answer is 21 minutes

Step-by-step explanation:

We use the equation Xf = Xo + vt

1) At 1:00 PM, child one leaves the starting point heading north at a constant velocity of 6 mi/hr or .1 [mi/min] (divide by 60 to convert from [mi/hr] to [mi/min])

2) He walks for 15 minutes before kid 2 starts walking. In 15 minutes he is able to cover 1.5 [mi]

  • x_{1f1} =x_{o} +v_{1} t_{1} \\x_{1f1} =0+.1(15)\\x_{1f1} =1.5 [mi]

3) Now, child 2 starts walking and we know that when the range reaches 3 miles, they won´t be able to communicate. So the sum of the final position of child 1 and child 2 must be 3[mi]

  • Child 1 final position => x_{1f} = x_{1f1} +v_{1} t\\x_{1f} =1.5+v_{1} t
  • Child 2 final position => x_{2f} =0+v_{2} t

4) Sum the equations and equate to 3

  • x_{1f} +x_{2f} =3

5) Substitute the values we already know

  • 1.5+v_{1} t+v_{2}t=3\\ 1.5+.1t+.15t=3\\1.5+.25t=3\\t=\frac{3-1.5}{.25} \\t=6 [min]

6) in 15 + 6 minutes they will be 3miles apart

7) In 21 minutes they will still be able to communicate with one another.

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3 years ago
If 2x-1 is a factor of 16x^4-24x^3+2x+f find f
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Step-by-step explanation:

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Belle runs 16 times around a track that measures 1/4 mile long.
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16/4 which could be simplified to be the whole number 4
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If the legs of a right triangle are x, (2x - 1) and its hypotenuse is (2x + 1), what is the value of x?​
Ber [7]

Answer:

x=8

Step-by-step explanation:

(2x + 1)² = x² + (2x - 1)² = x² + (2x - 1)(2x - 1)

(2x + 1)(2x + 1) = x² + 4x²-2x-2x+1

4x²+2x+2x+1 = 5x²-4x+1

4x²+4x+1 = 5x²-4x+1

0= 5x²-4x²-4x-4x+1-1

0= x²-8x

x²-8x=0

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