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3 years ago

I don't get this please help me

Mathematics

2 answers:

Semmy [17]3 years ago

7 0

There are 28 shades: 72 not shaded

sveta [45]3 years ago

4 0

There are 28 squares in the box. Hope this helps you

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15 kg equals how many grams

Slav-nsk [51]

Answer:

15,000g

Step-by-step explanation:

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3 years ago

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Determine the quotient of 1 and 2 over 3 divided by 4 over 5.

sukhopar [10]

Answer:

me tooo plzzz some one slove this

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3 years ago

A population of values has a normal distribution with μ = 247 and σ = 62.2. You intend to draw a random sample of size n = 16. (

nadya68 [22]

Answer:

a) $z = \frac{295.2-247}{62.2}=0.772$

And using the normal distribution table or excel we got:

$P(Z>0.772) = 1-P(Z$

b) $z = \frac{295.5 -247}{\frac{62.2}{\sqrt{16}}}= 3.119$

And we can use the normal standard table or excel in order to find the probability and we got:

$P(z>3.119) =1-P(Z$

Step-by-step explanation:

For this case we know that the random variable of interest is normally distributed with the following parameters:

$X \sim N (\mu = 247, \sigma =62.2)$

Part a

We want to find this probability:

$P(X>295.2)$

And we can use the z score formula given by:

$z = \frac{X-\mu}{\sigma}$

Replacing we got:

$z = \frac{295.2-247}{62.2}=0.772$

And using the normal distribution table or excel we got:

$P(Z>0.772) = 1-P(Z$

Part b

We select a random sample of size n = 16 and we try to find this probability:

$P(\bar X >295.2)$

And we can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$z = \frac{295.5 -247}{\frac{62.2}{\sqrt{16}}}= 3.119$

And we can use the normal standard table or excel in order to find the probability and we got:

$P(z>3.119) =1-P(Z$

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3 years ago

A student fit the line shown below to the data in the scatter plot. Which statement about the student's line is true?

Furkat [3]

Answer:

C. It is not a good fit because there are no points on the line.

Step-by-step explanation:

In order for a line to be a good fit for a data set represented as a scatterplot, the line must follow the general trend of the data in the scatterplot. This line does not follow the general trend of the data on the scatterplot, thus option (C) is the best statement to describe the situation.

C. It is not a good fit because there are no points on the line.

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3 years ago

Solve y: 6.3 = 0.9y<br><br> Solve x: x + 7.72 = 19<br><br> What is y? What is x?

Ulleksa [173]

Solve y: 6.3 = 0.9y
6.3/0.9 = 0.9y/09
y = 7

Solve x: x + 7.72 = 19
x + 7.72-7.72 = 19 - 7.72
x = 11.28

What is y? 7 What is x? 11.28

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4 years ago

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