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3 years ago

Not school work. y’all i need to know something.

Mathematics

2 answers:

LUCKY_DIMON [66]3 years ago

4 0

Ask your teachers if you can still turn them in

Alexxandr [17]3 years ago

3 0

it really depends on how many grades the project are worth and also good job on your grades mine and not the best no need to worry it will be ok I promise and also just want to tell u something in case some one has not I love u and you are amazing and beautiful and don't let anyone tell u otherwise something you won't feel loved but just know I will always also you seen nice and cool I would love to get to know u also I will be here if u need someone ro talk to I will listen and do anything I can possibly do to help u have an amazing day always remember you are amazing strong and beautiful

You might be interested in

When two 6-sided dice are rolled, there are 36 possible outcomes. Find the probability that the sum is 8

katrin2010 [14]

Answer:

5/36

Step-by-step explanation:

Probability is the outcome that a event will occur

Probability = Expected outcome/Total outcome

Since two sided dice are rolled, the total outcome will be expressed as;

Total outcome = 36

Since we are to find the probability that the sum is 8, the values that gives a sum of 8a re;

(2,6)(6,2), (5, 3), (3,5), (4, 4)

The expected outcome = 5

Probability = 5/36

Hence the probability that the sum is 8 is 5/36

4 0

2 years ago

For the set C= {6,8}, determine n(C).

nasty-shy [4]

Step-by-step explanation:

Hey, there!!

C = {6,8}

n(C) means cardinality of set.

We define cardinality of set as the no. of elements present in set.

It contains 2 no. of elements.

so, its cardinality is n(C) is 2.

Hope it helps...

3 0

3 years ago

Flow meters are installed in urban sewer systems to measure the flows through the pipes. In dry weatherconditions (no rain) the

ziro4ka [17]

Answer:

a) $\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}$

$363.90 \leq \sigma^2 \leq 4430.80$

Now we just take square root on both sides of the interval and we got:

$19.08 \leq \sigma \leq 66.56$

b) For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

Step-by-step explanation:

423.6, 487.3, 453.2, 402.9, 483.0, 477.7, 442.3, 418.4, 459.0

Part a

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

On this case we need to find the sample standard deviation with the following formula:

$s=sqrt{\frac{\sum_{i=1}^8 (x_i -\bar x)^2}{n-1}}
And in order to find the sample mean we just need to use this formula:
[tex]\bar x =\frac{\sum_{i=1}^n x_i}{n}$