False.
Right triangles do not have to be congruent.
:)
Consider, in ΔRPQ,
RP = R (Radius of larger circle)
PQ = r (radius of smaller circle)
We have to find, RQ, by Pythagoras theorem,
RP² = PQ²+RQ²
R² = r²+RQ²
RQ² = R²-r²
RQ = √(R²-r²
Now, as RQ & QS both are tangents of the smaller circle, their lengths must be equal. so, RS = 2 × RQ
RS = 2√(R²-r²)
Answer:
Regular price: $429
35% discount: 278.85
5% tax: $13.94
Final cost: 292.79
Step-by-step explanation:
regular price=$429
0.35(429)=150.15
429-150.15=278.85
35% discount amount: $278.85
278.85(0.05)=13.94
278.85+13.94=292.79
Answer:
The value of the variable 'b' is 3 and GH is 9
Step-by-step explanation:
Given:
H is between G and I
Such that G - H - I
To Find:
GH = ?
Solution:
On Substituting HI we get
Substituting 'b' in HI and GI we get
Now, by Line Addition Property we get
Substituting 'HI' and 'GI' we get
The value of the variable 'b' is 3 and GH is 9
Answer:
Step-by-step explanation:
Depends on the tree.
If it's like a pine or spruce, then I would use maybe 2 inches lattitude. If it's really leafy with big leaves, perhaps a little more lattitude is needed, like maybe 1/2 a foot.
It also depends on the season. Unless the pine or spruce is covered with snow, I wouldn't change the latitude. If it is covered with snow, knock the snow off.
For something like a maple in winter, I'd reduce the latitude to 3 inches......
