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Xelga [282]
3 years ago
11

Find the area of the sector. Round the answer to the nearest tenth.

Mathematics
1 answer:
Marizza181 [45]3 years ago
3 0

Answer:

63.4

Step-by-step explanation:

Area of arc is (pi*(11)^2*(60/360))=63.4

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Select the correct answer.
Pani-rosa [81]

Answer:

its probably division property if equality

Step-by-step explanation:

because it has division in it

6 0
3 years ago
Choose all that correctly solve for the variable x
Ratling [72]
<h2>✔Answer</h2><h2>1. X = 3</h2><h2 /><h2>2. </h2><h2>\frac{7}{2}</h2><h2>3.</h2>

<h2>\frac{5}{6}</h2>

<h2>Hope it Helps❤</h2>
6 0
2 years ago
An object is launched at 19.6 m/s from a height of 58.8 m. The equation for the height (h) in terms of time (t) is given by h(t)
beks73 [17]
H(t) = Ho +Vot - gt^2/2

Vo = 19.6 m/s
Ho = 58.8 m
g = 9.8 m/s^2

H(t) = 58.8 + 19.6t -9.8t^2/2 = 58.8 + 19.6t - 4.9t^2

Maximun height is at the vertex of the parabole

To find the vertex, first find the roots.

58.8 + 19.6t - 4.9t^2 = 0

Divide by 4.9

12 + 4t - t^2 = 0

Change sign and reorder

t^2 - 4t -12 = 0 

Factor

(t - 6)(t + 2) =0 ==> t = 6 and t = -2.

The vertex is in the mid point between both roots

Find H(t) for: t = [6 - 2]/2 =4/2 = 2

 Find H(t) for t = 2

H(6) = 58.8 + 19.6(2) - 4.9(2)^2 = 78.4

Answer: the maximum height is 78.4 m
5 0
3 years ago
PLEASE HELP NOW NOW NOW PLEASE PLEASE HELP
bija089 [108]

Answer:

$46.00

Step-by-step explanation:

$46.00 - $20 + $5 = $21

7 0
3 years ago
What function corresponds to the ordered pairs shown in the table?
Anettt [7]

well, we know it's a line, and to get the equation of any line all we need is two points, let's pick two from the table hmmmm say let's use (-3 , -7) and (3 , 11)

(\stackrel{x_1}{-3}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{11}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{11}-\stackrel{y1}{(-7)}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{(-3)}}}\implies \cfrac{11+7}{3+3}\implies \cfrac{18}{6}\implies 3

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-7)}=\stackrel{m}{3}(x-\stackrel{x_1}{(-3)}) \\\\\\ y+7=3(x+3)\implies y+7=3x+9\implies y = 3x+2

6 0
3 years ago
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