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3 years ago

Triangles and rectangle

Mathematics

1 answer:

torisob [31]3 years ago

7 0

Step-by-step explanation:

Area of triangle (A1)

= 1/2 * b *h

= 1/2 * 1 * 1

= 1/2 ft

Area of rectangle (A2)

= L * b

= 3 *1

= 3 ft

Total area

= A1 + A2

= 1/2 + 3

= (1 + 6 ) / 2

= 7/2 ft²

= 3.5 ft²

Hope it will help :)

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3 years ago

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ElenaW [278]

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3 years ago

(1 point) Consider the function f(x)=2x3−9x2−60x+1 on the interval [−4,9]. Find the average or mean slope of the function on thi

OlgaM077 [116]

Answer: c = 4.97 and c = -1.97

Step-by-step explanation: <u>Mean Value Theorem</u> states if a function f(x) is continuous on interval [a,b] and differentiable on (a,b), there is at least one value c in the interval (a<c<b) such that:

$f'(c) = \frac{f(b)-f(a)}{b-a}$

So, for the function f(x) = $2x^{3}-9x^{2}-60x+1$ on interval [-4,9]

$f'(x) = 6x^{2}-18x-60$

f(-4) = $2.(-4)^{3}-9.(-4)^{2}-60.(-4)+1$

f(-4) = 113

f(9) = $2.(9)^{3}-9.(9)^{2}-60.(9)+1$

f(9) = 100

Calculating average:

$6c^{2}-18c-60 = \frac{100-113}{9-(-4)}$

$6c^{2}-18c-60 = -1$

$6c^{2}-18c-59 = 0$

Resolving through Bhaskara:

c = $\frac{18+\sqrt{1740} }{12}$

c = $\frac{18+41.71 }{12}$ = 4.97

c = $\frac{18-41.71 }{12}$ = -1.97

<u>Both values of c exist inside the interval [-4,9], so both values are mean slope: c = 4.97 and c = -1.97</u>

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4 years ago

Helpp !! I Dont Understand This !

makvit [3.9K]

How to solve shaded regions on a trapezoid is simple.
First find the area of the whole trapezoid, or W but it already gives us that as 21.66 in squared.
Next, find the area of the non shaded region, or NS.
3.8*4.6=17.48 in
Lastly, subtract the NS from the W.
21.66 -17.48 =
NS= 17.48 in squared.
W= 21.66 in squared.
S= 4.18 in squared.

The answer is B- 4.18 in Squared

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4 years ago

My. Whitney is 4392 m at its highest point. Bombay Beach, California, is 86 m below sea level (-86). What is the difference betw

andre [41]

Answer:

4306

Step-by-step explanation:

4392 - 86 = 4306

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3 years ago