Answer:
Draw the line segment AB = 7 cm.
Draw ray BX making an acute ∠ABX.
Along BX. mark off five points B1, B2, B3, B4 and B5. Join B2 to A.
Through B5 draw B5P || B2A, intersecting BA produced at P.
The point P so obtained is the required point which divides AB externally in the ratio 3:5.
Answer:
Will no explain too much in details.
The bottom rectangle has sizes 21cm*9cm, so its area is 189cm^2.
The remaining rectangle has sizes 6cm*7cm(16-9=7cm),so its area is 42cm^2.
The area of the object is 231 cm^2.
The perimeter is 21+9+16+6+(16-9)+(21-6) = 74 cm.
1) The y- axis is where x = 0, so the line "y = -1/2x - 3" will cross the y-axis when x = 0. You plug in "x = 0" into the equation, and get y = 0 -3, so y = -3. That means the line " y = -1/2x - 3" will cross the y-axis ar (0, -3)
2) If there are 2 parallel lines, then there is no solution, because the definition of parallel lines is, " 2 lines in the same plane, that never meet." That makes the solution inconsistent.
Answer:
that is impossible
Step-by-step explanation:
because you have 2 equations where y+z equal different numbers
$6.52 for the grab bag, divide that between two people and you get = $3.26
$6.52/2 = $3.26
$3.23 for the gumballs, divide that between two people and you get = $1.62
$3.23/2 = $1.62
$1.62 + $3.26 = $4.88
each of them have to pay $4.88
