Driving 40 miles in 2 hours is the answer
Answer:
(x-7) (x^2-5)
Step-by-step explanation:
x^3 -7x^2 -5x+35
Make 2 groups
x^3 -7x^2 -5x+35
Factor x^2 from the first group and -5 from the second group
x^2 (x-7) -5(x-7)
Now factor (x-7) out
(x-7) (x^2-5)
Triangle ACB and triangle ABD share one side AB. This means they have one side that is congruent; side AB
Angle ABD = Angle ABC
Angle BAC = Angle BAD
The pair of angles that are equal lie on the side AB
Hence, triangle ABC and triangle ABD are congruent by Angle-Side-Angle (ASA)
Answer: Second option
1) X^5Y/X^5= X^0Y= Y (Anything raise to power of 0 is 1)
2)(3mn)^1= 3mn
3)m^-4xM^5= M^-4+5= M
4) 5^-4x5^4= 5^-4+4= 5^0= 1
5) nm^3/n^3m= n^1-3m^3-1= n^-2m^2= m^2/n^2
6) (-2)^0= 1
therefore number 4 and 6 has the value of 1
Answer:
Step-by-step explanation:
Asymptotes 3
g(x) = 
Factors of denominator will be,
x² - 3x - 10 = x² - 5x + 2x - 10
= x(x - 5) + 2(x - 5)
= (x + 2)(x - 5)
Therefore, factored form of g(x) will be,
g(x) = 
Asymptotes 4
h(x) = 
= 
= 
= 
