The answer is (2b+1)(3b-4)
Let p be
the population proportion. <span>
We have p=0.60, n=200 and we are asked to find
P(^p<0.58). </span>
The thumb of the rule is since n*p = 200*0.60
and n*(1-p)= 200*(1-0.60) = 80 are both at least greater than 5, then n is
considered to be large and hence the sampling distribution of sample
proportion-^p will follow the z standard normal distribution. Hence this
sampling distribution will have the mean of all sample proportions- U^p = p =
0.60 and the standard deviation of all sample proportions- δ^p = √[p*(1-p)/n] =
√[0.60*(1-0.60)/200] = √0.0012.
So, the probability that the sample proportion
is less than 0.58
= P(^p<0.58)
= P{[(^p-U^p)/√[p*(1-p)/n]<[(0.58-0.60)/√0...
= P(z<-0.58)
= P(z<0) - P(-0.58<z<0)
= 0.5 - 0.2190
= 0.281
<span>So, there is 0.281 or 28.1% probability that the
sample proportion is less than 0.58. </span>
Answer:
Y=10x
(multiply 10 times the salamanders)
Step-by-step explanation:
a formula that can be used for this circumstance is a linear y=mx+b problem. for 1 salamander there are 10 frogs. so with this we can state that y=10x. whatever you plug into the x for the number of salamanders will give you the answer of how many frogs are in the pond. for example.
Y=10x
Y=10(3)
Y=30
30 frogs.
also because 10 is a nice number you can just multiply the number of salamanders times 10. 3*10=30
We have been given that there are 125 people and three door prizes.
In the first part we need to figure out how many ways can three door prizes of $50 each be distributed?
Since there are total 125 people and there are three identical door prices, therefore, we need to use combinations for this part.
Hence, the required number of ways are:
In the next part, we need to figure out how many ways can door prizes of $5,000, $500 and $50 be distributed?
Since we have total 125 people and there are three prices of different values, therefore, the required number of ways can be figured out by using permutations.
