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Luda [366]
3 years ago
12

Find the dividend if quotient is x–3, remainder is 7x–9 and divisor is x^2-2​

Mathematics
1 answer:
Elza [17]3 years ago
6 0

Answer:

\implies Dividend = x^3-3x^2+4x-3

Step-by-step explanation:

<u>Given </u><u>:</u><u>-</u><u> </u>

  • Quotient is x–3, remainder is 7x–9 and divisor is x^2-2 .

And we need to find out the Dividend. We know that ,

\implies Dividend = Quotient\times Divisor + Remainder

<u>Substituting</u><u> the</u><u> </u><u>respective</u><u> values</u><u> </u><u>:</u><u>-</u><u> </u>

\implies Dividend = (x-3)(x^2-2)+7x-9 \\\\\implies Dividend = x^3-2x-3x^2+6+7x-9 \\\\\implies Dividend = x^3-3x^2+4x-3

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Answer:

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4 years ago
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OlgaM077 [116]

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6 0
3 years ago
What is the value of k in the function ƒ(x) = 112 - kx if ƒ(-3) = 121?k = a0
nexus9112 [7]
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the area of a sector of a circle of radius 15cm is 110cm², calculate the angle of subtended at yhe center of the circle by the a
beks73 [17]

Answer:

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Step-by-step explanation:

The area is given by the formula ...

  A = (1/2)r²θ

where θ is the central angle in radians.

Filling in the given numbers, we have ...

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