Answer:
In bold.
Step-by-step explanation:
a. (x+5)^2 – 3x(x+5) x+5 is common
= (x + 5)(x + 5 - 3x)
= (x + 5)(5 - 2x)
b. (x + 5)(5 - 2x) = 0
x = -5, 2.5.
2a. Area of the square = (x + 5)^2
Area of triangle AEB
= 1/2 * base * height
I am assuming that H is the centre of AB , so
Area = x*x
= x^2.
2b
6x^2 = (x + 5)^2
6x^2 = x^2 + 10x + 25
5x^2 - 10x - 25 = 0
x^2 - 2x - 5 = 0
x = [-(-2) +/- sqrt(2^2 - 4*1*-5)] / 2
x = -1.45, 3.45.
(we ignore the negative).
If you find the square root of 10, you can see it is 3.16. So, 3.2 is greater than the square root of 10.
The <em><u>correct answer</u></em> is:
2
Explanation:
There are two directions from 0 on a number line, to the left and to the right.
Numbers to the left of 0 on a number line are negative numbers; numbers to the right of 0 on a number line are positive numbers.
The number 10 units to the left of 0 on a number line is -10, and the number 10 units to the right of 0 on a number line is 10; there are two answers.
C.) is the answer, I think
