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vredina [299]
3 years ago
15

Help me!! ASAP!! Plss just help me :( I will give u BRAINLYEST!!

Mathematics
1 answer:
konstantin123 [22]3 years ago
3 0
Well, if I were to come up with a real world situation that would involve finding the area of a circle then I think that a good real world situation would be finding the area of a circular sandpit.
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Find the mean, median, interquartile range and mean absolute deviation of the set of numbers. Round to the nearest tenth if nece
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The number set is needed to answer this :)
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A deli sells two types of sandwiches, tuna salad and BLT. The profit on the sandwiches is $1.50 for tuna and $2.50 for the BLT.
Korolek [52]
X = tuna, y = BLT

x + y = 30
6x + 9y = 240

3y = 60
y = 20

x = 10

20 BLTs for $2.50, 10 tuna for $1.50
7 0
3 years ago
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Evaluate 2sin(pi/3) cos(pi/3)
Sergeu [11.5K]
I got 0.03654595................... ignore me I'm dumb
7 0
4 years ago
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Let w(s,t)=f(u(s,t),v(s,t)) where u(1,0)=−6,∂u∂s(1,0)=5,∂u∂1(1,0)=7 v(1,0)=−8,∂v∂s(1,0)=−8,∂v∂t(1,0)=6 ∂f∂u(−6,−8)=−1,∂f∂v(−6,−8
Blababa [14]
w(s,t)=f(u(s,t),v(s,t))

From the given set of conditions, it's likely that you are asked to find the values of \dfrac{\partial w}{\partial s} and \dfrac{\partial w}{\partial t} at the point (s,t)=(1,0).

By the chain rule, the partial derivative with respect to s is

\dfrac{\partial w}{\partial s}=\dfrac{\partial f}{\partial u}\dfrac{\partial u}{\partial s}+\dfrac{\partial f}{\partial v}\dfrac{\partial v}{\partial s}

and so at the point (1,0), we have

\dfrac{\partial w}{\partial s}\bigg|_{(s,t)=(1,0)}=\dfrac{\partial f}{\partial 
u}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial u}{\partial s}\bigg|_{(s,t)=(1,0)}+\dfrac{\partial f}{\partial 
v}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial v}{\partial s}\bigg|_{(s,t)=(1,0)}
\dfrac{\partial w}{\partial s}\bigg|_{(s,t)=(1,0)}=(-1)(5)+(2)(-8)=-21

Similarly, the partial derivative with respect to t would be found via

\dfrac{\partial w}{\partial t}\bigg|_{(s,t)=(1,0)}=\dfrac{\partial f}{\partial 
u}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial u}{\partial t}\bigg|_{(s,t)=(1,0)}+\dfrac{\partial f}{\partial 
v}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial v}{\partial t}\bigg|_{(s,t)=(1,0)}
\dfrac{\partial w}{\partial t}\bigg|_{(s,t)=(1,0)}=(-1)(7)+(2)(6)=5
6 0
4 years ago
Help me with this question, explain how u get. I’ll give brainliest
gtnhenbr [62]

ANSWER: 1 SOLUTION

Step 1: Subtract 2x-1 from both sides.

x2−(2x−1)=2x−1−(2x−1)

x2−2x+1=0

Step 2: Factor left side of equation.

(x−1)(x−1)=0

Step 3: Set factors equal to 0.

x−1=0 or x−1=0

x=1

Answer:

x=1

7 0
3 years ago
Read 2 more answers
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