Answer:
option-C
Step-by-step explanation:
We are given row-echelon form
So, we can write equation from matrix as


Let's assume

now, we can find x and y




so, we get solutions as



where t can be any real numbers
Answer: the first answer choice
Step-by-step explanation: it’s nonlinear because it has a changing slope, and the graph crosses the y axis at -3
Her is the definition of an imaginary number An imaginary number is a complex number that can be written as a real number multiplied by the imaginary unit i, which is defined by its property i2 = −1. The square of an imaginary number bi is −b2. For example, 5i is an imaginary number, and its square is −25. Zero is considered to be both real and imaginary.
(Got that from google)
Answer:
i think the answer is A
Step-by-step explanation:
9/15 simplified is 3/5
Answer:
![\left[\begin{array}{cccc}-12&-13&13&|15\\7&-10&-3&|11\\7&14&5&\:\:\:|-5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D-12%26-13%2613%26%7C15%5C%5C7%26-10%26-3%26%7C11%5C%5C7%2614%265%26%5C%3A%5C%3A%5C%3A%7C-5%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
The system of equations is;
-12x-13y +13z =15
7x-10y-3z = 11
7x+14y +5z = -5
The coefficient matrix is ![\left[\begin{array}{ccc}-12&-13&13\\7&-10&-3\\7&14&5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-12%26-13%2613%5C%5C7%26-10%26-3%5C%5C7%2614%265%5Cend%7Barray%7D%5Cright%5D)
The constant matrix is ![\left[\begin{array}{c}15\\11\\-5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D15%5C%5C11%5C%5C-5%5Cend%7Barray%7D%5Cright%5D)
The augmented matrix is ![\left[\begin{array}{cccc}-12&-13&13&|15\\7&-10&-3&|11\\7&14&5&\:\:\:|-5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D-12%26-13%2613%26%7C15%5C%5C7%26-10%26-3%26%7C11%5C%5C7%2614%265%26%5C%3A%5C%3A%5C%3A%7C-5%5Cend%7Barray%7D%5Cright%5D)