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2 years ago

Evaluate ∛27 3 9 24 81 thanks.

Mathematics

2 answers:

Ugo [173]2 years ago

7 0

Answer:

the correct answer is 3.

Step-by-step explanation:

3×3×3= 27

Flura [38]2 years ago

4 0

Answer:

A. 3

Step-by-step explanation:

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A rectangular park, 90 meters by 60 meters, is to be built on a city block having an area of 9000 m^2. A uniform strip borders a

stealth61 [152]

Answer:

x = 10.52 m

Step-by-step explanation:

Given that,

Length of a park = 90 m

Width of a park = 60 m

Area, A = 9000 m²

A uniform strip borders all four sides of the park for parking. We need to find the width of the strip. Let it is x. Now the area becomes,

(90+2x)(60+2x) = 9000

$4x^2 +120x +180x =5400 = 9000\\\\x=10.52\ m$

So, the width of the strip is equal to 10.52 m.

8 0

2 years ago

A machine in a factory makes 20 gadgets every 1/4 hour. How many gadgets are made every hour?

Hoochie [10]

Answer:

80 machines

Step-by-step explanation:

If a machine makes 20 gadgets every fourth (1/4) of an hour, it makes 80 machines every hour (20*4).

7 0

3 years ago

Find the volume of the following solid. The solid between the cylinder f(x,y)equals=e Superscript negative xe−x and the region

PilotLPTM [1.2K]

It is hard to comprehend your question. As far as I understand:

f(x,y) = e^(-x)

Find the volume over region R = {(x,y): 0<=x<=ln(6), -6<=y <= 6}.

That is all I understood. It would be easier to understand with a picture or some kind of visual aid.

Anyways, to find the volume between the surface and your rectangular region R, we must evaluate a double integral of f on the region R.

$\iint_{R}^{ } e^{-x}dA=\int_{-6}^{6} \int_{0}^{ln(6)} e^{-x}dx dy$

Now evaluate,

$\int_{0}^{ln(6)}e^{-x}dx$

which evaluates to, 5/6 if I did the math correct. Correct me if I am wrong.

Now integrate this w.r.t. y:

$\int_{-6}^{6}\frac{5}{6}dy = 10$

So,

$\iint_{R}^{ } e^{-x}dA=\int_{-6}^{6} \int_{0}^{ln(6)} e^{-x}dx dy = 10$

7 0

3 years ago

Hamburgers cost $2.50 and cheeseburgers cost $3.50 at a snack bar. Ben has sold no more than $30 worth of hamburgers and cheeseb

Irina18 [472]

Given 2.50x + 3.50y < 30.

Where x represent the number of hamburgers and y represent the number of cheeseburgers.

Now question is to find the maximum value of hamburgers Ben could have sold when he has sold 4 cheeseburgers.

So, first step is to plug in y=4 in the given inequality. So,

2.50x+3.50(4)<30

2.50x+14 <30

2.50x<30- 14 Subtracting 14 from each sides.

2.50x< 16

$\frac{2.50x}{2.50}$ Dividing each sides by 2.50.

x<6.4

Now x being number of hamburgers must be an integer , so tha maximum value of x can be 6,

thus x = 6 hamburgers

So, the maximum value of hamburgers Ben could have sold is 6*2.5=$15

Hope this helps!!

8 0

3 years ago

A student has passed 60 percent of the 20 quizzes he has written so far successfully. If the student writes 50 quizzes during th

NikAS [45]

60% of 20 quizzes = 60/100*20 quizzes = 12 quizzes

Amount of quizzes remaining = 50 quizzes - 20 quizzes = 30 quizzes

He passes 80% of those 30 quizzes, so

80/100 * 30 quizzes = 24 quizzes

So, he passed 12 quizzes from the initial bunch and 24 quizzes from the rest, which totals to 12 quizzes + 24 quizzes = 36 quizzes.

Then, you see that he passed 36 quizzes, out of the total 50 quizzes, so the ratio is 36 quizzes / 50 quizzes = 36/50, which when converted as a percentage is 36/50 * 100% = 72%.

Therefore, he passed 72% of the quizzes for the entire year.

4 0

3 years ago