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denpristay [2]
3 years ago
12

When we rewrite a fraction as a decimal, are we changing the value of the fraction? hi so my teacher is asking this question on

this mini quiz thing and i have a horrible headache and dont feel like doing that right now. so pls help me out
Mathematics
2 answers:
AnnyKZ [126]3 years ago
6 0

Answer:

No, you are not changing the value.

Step-by-step explanation:

mash [69]3 years ago
4 0

Answer:

No, because then it would have different values and it wouldn't be rewriting it.

Step-by-step explanation:

Ex. 1/2. The decimal for this would be 0.5, right?

We aren't changing the value of the fraction. It is just another way of writing the value.

Hope this helped. :)

Also, I hope your headache goes away. Feel better soon. :D

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If the amount of waking time 4 year old children spend with their fathers each day is 42 minutes while the daily waking time spe
telo118 [61]

Answer:

7/60

Step-by-step explanation:

Because the question is phrased such that it asks "the ratio of time with father <em>to...."</em>, we know to put the time with father on top, or first. Similarly, since it is asked to put the ratio of time with the father to the time in daycare, we can put the daycare amount second/on the bottom. Therefore, we can write the ratio as

(42 minutes)/(6 hours)

To make both of these in terms of minutes to simplify it, we know that 60 minutes = 1 hour, so 1 hour / 60 minutes =1 . Since multiplying something by 1 keeps it the same, we can multiply our ratio by this amount. We want to multiply with the hour on top so the hours cancel out, as so:

\frac{42 minutes}{6 hours} * \frac{1 hour}{60 minutes}  = \frac{42 minutes * hours}{360 minutes * hours} = \frac{42}{360}

To simplify this even further, we can note that 6 is a factor of both 42 and 360*, so we can multiply this fraction by (1/6) / (1/6) to get

(42/360) * (1/6)/(1/6) = 7/60 as our final answer

If this doesn't come up immediately, you can always find the greatest common factor by listing the factors of each number and finding the highest one that fits both, e.g.

for 42: 42, 21, 14, 7 , 6...

for 360: 360,180, ... 6,5....

6 0
3 years ago
Points N and R both lie on circle O. Line segment RQ is tangent to the circle at point R.
ANEK [815]

Answer:

Perimeter ΔRON = 18.66 units

Step-by-step explanation:

Complete Question has these information given as well:

  • Circle with center O
  • RN = QN
  • RQ = 5\sqrt{3}
  • ON = 5 units
  • RQ is tangent

<em><u>Now, we draw an image according to the information given. THe image drawn is attached.</u></em>

<em><u /></em>

Looking at the figure, we can say the perimeter of triangle RON would be:

RON = OR + ON + RN

We know according to tangent theorem, QN = QR

RN is equal to that as well and RN = 5\sqrt{3}

Now,

OR and ON is the radius, which is "5"

Perimeter of RON = 5 + 5 + 5\sqrt{3} = 10 + 5\sqrt{3} = 18.66 units

<u>Perimeter ΔRON = 18.66 units</u>

4 0
4 years ago
Read 2 more answers
1/3x=5/12 show your work
insens350 [35]

Answer:

4/5 or 0.8

Step-by-step explanation:

1/3x = 5/12

<em>cross</em><em> </em><em>multiply</em>

(12×1) = (5×3x)

<em>divide</em><em> </em><em>through</em> <em>by</em> <em>1</em><em>5</em>

x = 12/15

x = 4/5 <em>o</em><em>r</em><em> </em>0.8

3 0
3 years ago
If a mole of sodium chloride weighs approximately 58 grams, and you have 29 grams of sodium chloride, how many moles of sodium c
Alexus [3.1K]
The answer is <span>A.0.5 moles 

</span><span>a mole of sodium chloride weighs approximately 58 grams: 1 M - 58 g
</span><span>you have 29 grams of sodium chloride, how many moles of sodium chloride do you have: xM - 29g

1 M : 58g = x : 29 g
x = 1 M : 58g * 29 g = 0.5 M</span>
7 0
3 years ago
Sonny has $75 to spend. The purchase he wants to make requires$93. If he borrows the extra money that he needs, how much does he
lidiya [134]
All you gotta do is subtract both of the numbers to get how much you need.

93 - 75 = 18

We can double check to see if it's right by using addition

18 + 75 = 93

Sonny needs to borrow 18$ to meet his required amount :D
7 0
3 years ago
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