Answer:
No, it is not possible
Explanation:
Humans use the ABO blood group system where the A and B alleles are dominant over allele O but codominant with one another.
This system is such that;
Type A can only have genotype: iAiA or iAi
Type B can only have genotype: iBiB or iBi
Type AB can only have genotype: iAiB
Type O can only have genotype: ii
According to this question, a woman has blood Type A (iAiA or iAi) and her baby has blood Type AB (iAiB). This means that the father definitely contributed the allele B in order to have a baby with type AB. It also means that, according to the question, IT IS NOT POSSIBLE FOR A "Type A" father to produce that baby (see the punnet square attached).
Note: The father must contain an allele B in his genotype i.e. the father must be either type B (iBiB or iBi) or type AB (iAiB)
Answer: First, the bacteria will adjust and then it will divide.
Explanation:
Once the bacterial species is put into the cultural medium, there the bacteria present in the medium needs to acclimatize in the medium and then start growing.
There is a lag phase before the log phase because first the bacteria will adjust into the medium and then start dividing.
As we know that the growing medium contains amino acids, growth factors, enzymes and many more things which first needs to be utilized by the bacteria and then it will start dividing.
Answer: Some sticklebacks were stranded in lakes that were formed in the ice age
Answer:
Uno de los progenitores es heterocigoto para color naranja (Nn) y el otro parental es homocigoto recesivo para gris (nn). Al haber una cruza entre un homocigoto recesivo y un heterocigoto, la 50% de la progenie expresa color naranja (Nn), mientras que el otro 50% expresa color gris (nn).
Explanation:
<u>Datos disponibles:</u>
- Cruce entre peces naranjas y peces grises
- 50% de la F1 son peces grises
- Naranja dominante sobre gris
Podemos nombrar el alelo dominante para color naranja <em>N</em>, y al alelo recesivo para color gris <em>n</em>.
Para que en un cruce entre dos fenotipos distintos, el 50% de la primer camada exprese uno de estos fenotipos, entonces uno de los parentales debe ser heterocigoto, mientras que el otro parental debe ser homocigoto recesivo. De esta forma 50% de la primera generación expresara uno de los fenotipos, mientras que el otro 50% expresará el otro fenotipo.
Supongamos que uno de los parentales lleva el genotipo <em>Nn</em>, y el otro parental es <em>nn</em>.
Cruce:
Parental) Nn x nn
Gametas) N n n n
Fenotipos) Naranja Gris
Cuadro de Punnett) N n
n Nn nn
n Nn nn
F1) 2/4 = 1/2 = 50% de la progenie tendrá genotipo heterocigoto, Nn
2/4 = 1/2 = 50% de la progenie tendrá genotipo homocigota recesivo,
nn
50% de la progenie será color naranja (Nn)
50% de la progenie será color gris (nn)
Answer : states of mmmatter... This is because elements at the right are majorly non metal and are liquid or gas at room temperature while those at the left are metal and mostly solid at room temperature
